8 coins are tossed. Whats is the probability that one and only one turns up head ?

Options
1) 1/256
2) 1/32
3) 1/64
4) 1/128

• 8/2^8=8/256=1/32. where 2^8 is the sample space and we cn get only one head in 8 ways..So answer is (2).
• 9 years agoHelpfull: Yes(23) No(1)
• total number of outcomes = 2^8 = 256
  number of favourable outcomes = 8. { TTTTTTTH, TTTTTTHT, TTTTTHTT, TTTTHTTT, TTTHTTTT, TTHTTTTT, THTTTTTT, HTTTTTTT }
  answer = 8/256 = 1/32
• 9 years agoHelpfull: Yes(19) No(1)
• 8c1(1/2)(1/2)^7=1/32
• 8 years agoHelpfull: Yes(6) No(1)
• One head and seven tails would have eight positions where the head can come.
  Thus, 8 × (1/2)8 = (1/32)
• 8 years agoHelpfull: Yes(1) No(0)
• only one turns up head in 8 times the n0 of event is 8
  HTTTTTTT THTTTTTT TTHTTTTT TTTHTTTT TTTTHTTT TTTTTHTT TTTTTTHT TTTTTTTH
  AND TOTAL OUTCOMES IS 2^8 = 256
  required probability = 8/256, = 1/32
  hence option 2 is correct
  
• 7 years agoHelpfull: Yes(1) No(0)
• 8 coin tossed=n(s)=2^8=256
  Prob of getting only 1 head is n(e)=8
  
  Therefore n(e)/n(s)=8/256=1/32
• 7 years agoHelpfull: Yes(1) No(0)
• 1/32 because in 8 ways only one head can come and there are 256 total outcomes therefore probability is 1/32.
• 5 years agoHelpfull: Yes(1) No(0)
• 8c1*((1/2)^1)*((1/2)^7)=1/32
• 7 years agoHelpfull: Yes(0) No(0)
• 8c1/2(pw8) ans
• 7 years agoHelpfull: Yes(0) No(0)