1! + 2! + .... 50! = ?

a. 3.1035*10^64
b. 2.1021* 10 ^ 65
c. 3.1035*10^63
d. 3.1035*10^62

• as 50!=3.0414093202×10^64
  refer:-http://en.wikipedia.org/wiki/Factorial
  so by the below mentioned approach option a is correct....
  
  ans:-(a)
• 14 years agoHelpfull: Yes(10) No(4)
• this summation can be defined by reverse recurssion
  if you want the sum of the factorials from 1 to n then start with
  s(n) = n
  and then
  s(i) = i * ( 1 + s(i+1) )
  and s(1) gives the summation
  for example if n=4 we have
  s(4)=4
  s(3)=3*(4+1)=15
  s(2)=2*(15+1)=32
  s(1)=1*(32+1)=33
  which agrees with
  1!+2!+3!+4! = 1+2+6+24
  
  using a computer program and using this recurssion method I get the sum as
  31035053229546199656252032972759319953…
  
  this is wat i can help...
• 14 years agoHelpfull: Yes(8) No(6)