if 20 men or 24 women or 40 boys can do a job in 12days working for 8 hours a day.how many men working with 6 women and 2 boys take to do a job four times as big working 5 hours a day for 12days?

• Amount of work done by 20 men = 24 women = 40 boys or amount of work done by 1 man = 1.2 women = 2 boys.
  
  Let us therefore, find out the amount of men required, if only men were working on the task, to complete the new job under the new conditions.
  
  And then make adjustments for the women and boys who are already employed on the task.
  
  The man hours required to complete the new task = 4 times the man hours required to complete the old task. (As the new task is 4 times as big as the old task)
  
  So, the new task is 20 * 12 * 8 * 4 men hours task.
  
  Let 'n' be the number of men required to complete the new task.
  Equating the men hours of task, we get 20 * 12 * 8 * 4 = n * 5 * 12. Or n = 128.
  
  The new task will require 128 men, if only men worked on the task to complete it.
  
  However, the problem states that 6 women and 2 boys are working on the job.
  
  6 women are the equivalent of = 5 men and 2 boys = 1 man.
  
  i.e., the equivalent of 5 + 1 = 6 men are already working on the project.
  
  Therefore, 122 more men are required to work with 6 women and 2 boys to complete the task.
• 12 years agoHelpfull: Yes(22) No(6)
• my answer is 122
• 12 years agoHelpfull: Yes(6) No(5)
• 20m=24w=40b
  w=5/6 m
  b=1/2 m
  6w+2b=5m+m=6m
  20*8 =x*5
  x=32
  no of men =32-6=26m
• 9 years agoHelpfull: Yes(4) No(1)
• my last ans was wrong
  answer is 122 men...
  24w-96hrs-xw
  1-8hrs-[x/24]
  1w-1hr-[x/24*96]
  6w-60hr-[x*6*60/24*96] = 5x/32 work
  
  40b-96hr-x
  2b-60 hr - [x*2*60/40*96]= x/32
  
  so total work done by 6w and 2 b = 6x/32
  men do [4x-6x/32]= 122x/32
  
  96 hrs- x work - 20 men
  1 hrs - x work - 20*96 men
  1 hrs- 1 w - [(20*96)/x] men
  60 hrs - 122x/32 work -- [(20*96*122x)/(x*60*32)] = 122
  so answer is 122 men
• 12 years agoHelpfull: Yes(3) No(2)
• using m*d*w rule we get
  (20*12*8)*4=x*5*12
  =>x=128
  now 6 women=5 men and 2 boys=1 man;
  so already we have 5m+1m=6m then 128-6=122
  so 122 men are required .
• 9 years agoHelpfull: Yes(2) No(0)
• x=126 men
  
  sol=
  m*w*d=m*w*d rule will apply here;
  (20+24+40)*12*8=(x+6+2)*12*5;
  x=126;
  ans
• 12 years agoHelpfull: Yes(1) No(6)
• @neha: plz explain..
  
• 12 years agoHelpfull: Yes(1) No(1)
• ans-26
  24women............96hours...............1work
  6women...............60hours.............6*60/96*24=5/32
  
  40boys...............96hours................1work
  2boys..................60hours...............2*60/40*96=1/32
  
  remaining work=1-[5/32+1/32]
  1-6//32=13/16
  
  20men.........1hours.........1/96work
  1men............1hours.........1/96*20work
  
  1/96*20work.............1hours..........1men
  1work...............60hours...........96*20/60=32
  13/16work.............60hours............32*13/16=26men.
  
• 9 years agoHelpfull: Yes(1) No(0)
• use the formula
  (M1*D1*E1)/V1 = (M2*D2*E2)/V2
  where M=no of men
  D=duration of work
  E=efficency of the work
  V=volume of the work
  A/Q:
  M1=20, M2=X
  D1=12*8 ,D2=12*5
  E1:E2=4:1
  V1=V2=1(SAME JOB)
  
  (20*12*8*4) = X*12*5*1
  X=122(MEN)
• 8 years agoHelpfull: Yes(1) No(1)
• use m * d * w formula
  (20 * 12 * 8) * 4 = x * 12 * 5 [ multiply with 4 because job is done 4 times ]
  after solving this we will get x =128men [ total number of men working ]
  now, look it is given 20men or 24 women or 40 boys that mens 20men=24 women = 40boys
  ab hmlog 1men nikalenge kikitna barabar h woh women aur boys ke...
  20men=24women
  => m= 24/20
  =>m = 1.2 women
  now in case of boys 1 men is equal to 20m=40b
  => m=40/20
  => m= 2 boy ohk
  now it is given that 6women and 2 boys lready working now we will use 1men is equal to how much women and boy which we have founf earlier
  look, 24women=20men [from 1st part of question]
  1 women = 20/24 men
  6women=20/24*6 men => 5 men [ 6 women = 5 men].......(1)
  and we already know that [2 boy is equal to 1 men]....(2)
  now, 6women + 2 boys = 5 men + 1 men = 6 men (using 1 and 2 )
  now simply deduct 128 - 6 = 122 [ total men - men already working i.e 6 ]
  so 122 answer
• 8 years agoHelpfull: Yes(1) No(0)
• i think 126 men required
• 12 years agoHelpfull: Yes(0) No(5)
• answer is 26 men...
  24w-96hrs-xw
  1-8hrs-[x/24]
  1w-1hr-[x/24*96]
  6w-60hr-[x*6*60/24*96] = 5x/32 work
  
  40b-96hr-x
  2b-60 hr - [x*2*60/40*96]= x/32
  
  so total work done by 6w and 2 b = 6x/32
  men do [x-6x/32]= 26x/32
  
  96 hrs- x work - 20 men
  1 hrs - x work - 20*96 men
  1 hrs- 1 w - [(20*96)/x] men
  60 hrs - 26x/32 work -- [(20*96*26x)/(x*60*32)] = 26
  so answer is 26 men
• 12 years agoHelpfull: Yes(0) No(6)
• (20+24+40):12*8:1=(x+6+2):12*5:4*1
  accordind to ques job is 4 times than pre
  (20+24+40)*1/12*8 = (x+6+2)*4/(12*5)
  solv n find the x
• 12 years agoHelpfull: Yes(0) No(1)
• answer is 122-6=116
• 12 years agoHelpfull: Yes(0) No(1)
• Let’s try solving this Problem using ratio approach.
  Amount of work done by 20 men = 24 women = 40 boys or 1 man = 1.2 woman = 2 boys.
  
  Let us therefore, find out the amount of men required, if only men were working on the job, to complete the new job under the new conditions and then make adjustments for the women and children working with the men.
  
  The man hours required to complete the new job = 4 times the man hours required to complete the old job. (As the new job is 4 times as big as the old job)
  Let ‘n’ be the number of men required.
  
  20×12×8=n×5×12×4 or n=8
  
  8 men working will be able to complete the given job.
  
  However, the problem states that 6 women and 2 boys are working on the job.
  
  6 women = 612= 5 men and 2 boys = 1 man. The equivalent of 5+1=6 men are already working.
  .
• 9 years agoHelpfull: Yes(0) No(0)
• let us take number of men = x
  now ,
  24 w = 20 m
  1 w = 20/24 m
  and
  40 b = 20 m
  so , 1 b = 20/40 m
  
  now ,according to the second conditon
  total number if people in terms of men =
  x +(20/24)*6+(20/40)*2 = x+ 5+1 = (6+x) men
  now a.t.q
  (m1)(d1)(t1)=(m2)(d2)(t2)
  20*12*8= (6+x)*5*12
  20*8=(6+x)*5
  32=6+x
  X=26
  
• 9 years agoHelpfull: Yes(0) No(0)