two cyclists start biking from a trail's start 3hrs apart.the second cyclist travels at 10kmph and starts 3hrs after the first cyclist who is travelling at 6mph .how long will it take the second cyclist to catch up with the first?

• By the time , second cyclist starts, he has covered 18 miles in 3 hrs.
  Extra Distance of 18 miles will be covered by second cyclist in 18/(10-6) = 18/4 = 9/2 hrs = 4.5 hrs
• 11 years agoHelpfull: Yes(8) No(10)
• ans 4.5
  total time travelled by 1st cyclist is 7.5
  2nd cyclist started chasing only after 3 hours. so time required to catch the 1st cyclist is 7.5-3=4.5 hrs.
  
• 11 years agoHelpfull: Yes(7) No(1)
• some1 pls explain this puzzle..
  
• 11 years agoHelpfull: Yes(5) No(1)
• let 2nd catch up wid the 1st in t hours....he has to cover the same distance in t hours,which is covered by 1st in (3+t)hours
  t*10=(3+t)*6
  t=4.5 hours
• 11 years agoHelpfull: Yes(5) No(1)
• convert 6mph into kmph we get 1.6*6=9.6kmph
  now distance between them is 9.6*3=28.8km
  t=d/relative speed =28.8/0.4=72hrs
• 11 years agoHelpfull: Yes(3) No(8)
• total distans
  10*t=6*3+6*2+6*t
  t=30/4 = 7.5 hrs
  
• 11 years agoHelpfull: Yes(2) No(4)
• ACCORDING TO QUESTION
  6T=10(T-3)
  T=40/3
• 11 years agoHelpfull: Yes(0) No(2)