the cost of cup is twice as that of a saucer.if the cost of a cup increases by 13% and that of a saucer increases by 19% by how much percent would the cost of 6 cups and 6 saucers increase?

• let initial cost of cup be 2s and cost of saucer be s.
  cost of 6 cups and 6 saucers = 18s
  Final cost of 6 cups and 6 saucers = 6*( 1.13*2s + 1.19s) = 6*3.45s = 20.7s
  
  % increase in cost = 100*2.7/18= 270/18 = 15%
• 12 years agoHelpfull: Yes(46) No(1)
• CUP=X,SAUCER=2X 6CUP+6SAUCER=18X, 6CUPIF 13% INC+6 SAUCER 19%INC=21.06 AVG INC =((21.06-18)/18)*100
  =17%INCREASE
• 12 years agoHelpfull: Yes(2) No(15)
• GARIMA IS CORRECT 15%
• 12 years agoHelpfull: Yes(1) No(3)
• 15% increases.
  
• 12 years agoHelpfull: Yes(1) No(2)
• Its 15 or 17 ?
• 12 years agoHelpfull: Yes(1) No(0)
• prasath is correct..itz 17%
  
• 12 years agoHelpfull: Yes(0) No(3)
• all of u .. are wright
  
• 12 years agoHelpfull: Yes(0) No(4)