a candidate who gets 20% of the maximum marks in an exam,fails by 30 marks,but another candidate who gets 32% of the maximum marks gets 42 marks more than the minimum pass marks find the % of pass marks?

• If max marks are x, then
  
  0.2x+30 = 0.32x - 42
  0.12x = 72
  x= 600
  passing marks = 120+30=150
  % of passing marks = 100*150/600= 25%
• 11 years agoHelpfull: Yes(42) No(0)
• 25% is the answer
• 11 years agoHelpfull: Yes(5) No(3)
• i think 150
• 11 years agoHelpfull: Yes(3) No(2)
• ya ya .the question is excayly correct
• 11 years agoHelpfull: Yes(1) No(5)
• 1st person got 20% and failed by 30.
  2nd person got 32% and got 42 more marks than required.
  =>32%-20%=30+42.
  =>12%72.
  if 12%=72
  100%=?
  cross multiply them, we get, 100=600 marks.
  =>20% of 600 is 120
  He needs 30 more marks to pass.so 120+30=150 is the marks need.
  150 is 25% of 600.
  so 25% is the answer .
• 5 years agoHelpfull: Yes(1) No(0)
• 20% of x+30=pass
  32%of x=20% of x+30+42
  12%of x=72
  then x=600 then
  30=(x/100) * (600) the value is 5% finally 20%+5%=25%
• 8 years agoHelpfull: Yes(0) No(0)
• suppose maximum marks are x,
  failed candidate got 20%marks in exam and gets 30 marks less than passing marks
  passed candidate gets 32% marks and gets 42 marks more than min marks
  so,
  0.2x + 30 (Passing Marks)
  0.32x - 42 (Passing Marks)
  so,
  0.2x + 30 = 0.32x - 42
  0.12x = 72
  x = 600
  passing marks : 0.12 (600) + 30 =150
  passing % = (100*150)/600 = 25%
• 8 years agoHelpfull: Yes(0) No(0)
• let total marks be x
  now student A got 20% x= x/5
  now 30+x/5 = passing marks
  student B got 32%x = pm +42
  
  on solving we get total marks as 600
  then passing marks = 150
  which is 25% of 600.
• 7 years agoHelpfull: Yes(0) No(0)
• f max marks are x, then
  
  0.2x+30 = 0.32x - 42
  0.12x = 72
  x= 600
  passing marks = 120+30=150
  % of passing marks = 100*150/600= 25%
• 5 years agoHelpfull: Yes(0) No(0)