a tree of height 36 m is on edge of the road, because of the wind a part of tree fall and touches the other side of the road..the road is 12 m wide then what will be the height of the broken part?

• let tree breaks at x m
  height of boken part=(36-x)m
  top touches road edge ie base=12 m
  (36-x)^2=x^2+12^2(pythagorous theorem)
  solving you get x=16m
  height of broken part=36-16=20m ANS..
  
• 12 years agoHelpfull: Yes(48) No(6)
• if the broken part is 'x'..
  by pythagoras theorem we have :
  x^2=(36-x)^2 + 12^2..
  that gives the answer 20m.
  
• 12 years agoHelpfull: Yes(11) No(6)
• suppose 'x' is the broken part
  so x^2=12^2+(36-x)^2
  x=16
• 12 years agoHelpfull: Yes(10) No(11)
• Let breaks part = x
  height of the tree in the broken part = 36-x
  top of the road edge in base = 12 m
  so consider Pythagoras theorem ,
  a^2= b^2 + c^2
  so let
  x^2 = (36- x)^2 + 12^2
  x = 36 - x + 12
  2x = 24
  x= 12
  so broken part = 36 -12 = 24
  ANS : 24
• 11 years agoHelpfull: Yes(2) No(3)
• by th egiven data we can form a right angled triangle. hence height of the tree can be calculated using pythagoras theorem.. ans:37.947m
• 12 years agoHelpfull: Yes(1) No(11)
• x+y=36
  y^2=x^2 + 144
  upon solvng x=20m
• 12 years agoHelpfull: Yes(1) No(4)
• x^2=(36-x)^2+12^2
  ans :20
• 12 years agoHelpfull: Yes(1) No(5)
• yes...... now i understood
  
• 12 years agoHelpfull: Yes(0) No(3)