In this question a b means a raised to the power b find the remainder when 41 77 is divided

Answer is 6
Solution:
(41^1)%7=6
(41^2)%7=1
(41^3)%7=6
thus power is odd then Answer is 6..
12 years agoHelpfull: Yes(13) No(3)
it can be written as (7*6-1)^77/7
hence ans is 6 becoz it is of d form (mx-1)^n/m......and if n is even the remainder will be 1 and if it is odd remainder will be m-1.
12 years agoHelpfull: Yes(12) No(1)
41^77 mod 7
(7*5+6)^77 mod 7

(6)^77 mod 7
(6)^76.6^1 mod 7
(7-1)^76 .6 mod 7
(-1)^76 .6 mod 7
6 mod 7=6 ans)
12 years agoHelpfull: Yes(5) No(0)
41^77 can be written as (7*5+ 6)^77
hence, 6^77 can be written as {(6^2)^38}.6
= 36^38.6
=(7*5+1)^38.6
=1.6
=6=ans
12 years agoHelpfull: Yes(2) No(3)
answer=6.
12 years agoHelpfull: Yes(2) No(0)
6 is the ans
12 years agoHelpfull: Yes(1) No(2)
41^77 divided by 7
sol:- first divide 41 by 7
remainder will be 6
now
6^1 div by 7 rem is 6
6^2 div by 7 rem is 1
6^3 div by 7 rem is 6
so for each even no. power you get rem as 1 and
for each odd no. power you get rem as 6
therefore ans will be 6 as power 77 is odd.
8 years agoHelpfull: Yes(0) No(0)

In this question a^b means a raised to the power b . find the remainder when 41^77 is divided by 7