Teda and meda take two triangles having angles Xt>Yt>Zt and Xm>Ym>Zm respectively. Teda maximizes the angle Xt and Meda Maximizes the angle Ym,Then what is the least value of Xt-Ym.?
(a)2 (b)20 (c)88 (d)none

• We will have to limimt ourselves for an integral solution or integral measurement of degrees.
  Since, both are going for maximising the angles, the maximum possible angle in a triangle is 178°, the other two being 1° each.
  So, as Teda has to maximise X(t), he will choose X(t)=177°, Y(t)=2° and Z(t)=1°.
  Similarly, as Meda has to maximise Y(m), he will look for values of Y(m) so that it is just behind of X(m).
  So, he will put X(m)=90°,Y(M)=89° and Z(m)=1°.
  
  Therefore, the needed difference = 177° - 89° = 88°.
  
  Hence ,the result would be 88°.
• 9 years agoHelpfull: Yes(14) No(2)
• 
  
  ans is 2
• 9 years agoHelpfull: Yes(1) No(5)
• (x+y+z)=180
  both teda and meda maximize, any angle value should be equal at maximum of angles therefore least difference will be 0.
• 9 years agoHelpfull: Yes(1) No(4)
• Teda :
  xt>yt>zt
  now lets see the probable range of xt
  90zm
  probable range of ym:
  2
• 9 years agoHelpfull: Yes(1) No(1)