In a right angled triangle we have hypotenuse as h a and b as base and perpendicular from the centre

ans=ab/a+b
according to property of triangle by joining the mid point of hypotenuse and perpendicular we got two triangles of hypotenuse=h/2 and base=a/2.
so side of square =a/2 and b/2
as we know that side should be equal
so put a=b in the option we get a/2 and b/2 in the first option.
9 years agoHelpfull: Yes(20) No(4)

area of triangle+area of triangle+area of square=area of full triangle
0.5 *a-x*x + 0.5*b-x*x + x^2=0.5ab=
x=ab/a+bans
9 years agoHelpfull: Yes(7) No(0)
mid point of hypotenuse to right angle vertices is called median and its length is equal to half of hypotenuse.
according to question that median is diagonal of formed square which has length h/2
let side of square is x
rt2*x=h/2
=>rt2*x=rt(a^2+b^2)/2
x=rt(a^2+b^2)/(2*rt2)
9 years agoHelpfull: Yes(2) No(2)
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a^2+b^2=h^2

according to property of triangle by joining the mid point of hypotenuse and perpendicular we got two triangles of hypotenuse=h/2 and base=a/2.

let side be is x =>x=a/2 x=b/2 =>2x=a/2+b/2 =>x=a+b/4
they ask x ^2 =>x^2=a/2 *b/2=ab/4
=> x=ab/4(a/4+b/4) =ab/a+b
9 years agoHelpfull: Yes(1) No(0)
let the side of the square is x
base=a
perpendicular =b.
then if the hypotenuse as h , h/2 will be its half.
the for the triangle of hypotenuse as h/2.
(h/2)^2=(a-x)^2+x^2 _______(1)
for the second triangle of hypotenuse as h/2.
(h/2)^2=(b-x)^2+x^2________(2)
from (1) & (2),
(a-x)^2=(b-x)^2
a^2+x^2-2ax=b^2+x^2-2bx
a^2-b^2=2ax-2bx
(a+b)(a-b)=2x(a-b)
x=(a+b)/2
hence ans =(a+b)
9 years agoHelpfull: Yes(1) No(1)
ans=AB/A+B

area of big triangle=area of first small triangle+area of second small triangle+area of square formed inside triangle
8 years agoHelpfull: Yes(0) No(0)
Area of triangle+area of triangle+area of square = area of full triangle
0.5 *a-x*x + 0.5*b-x*x + x^2=0.5ab
x=ab/a+b
Which is the answer
8 years agoHelpfull: Yes(0) No(0)

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