46) 60 men can complete a piece of work in 40 days. 60 men start the work but after every 5 days 5 people leave. In how many days will the work be completed?

• work will not be completed, since no of persons decreases no days will increases.
• 12 years agoHelpfull: Yes(27) No(2)
• the work wl not be completed coz we will remain wd no person after 60 days n till than nly 13/16 part f d wrk. . hence 3/16 part f the wrk will be remained undone :)
  since 60 men cn comlpete the wrk in 40 days. . so1 men's 1 day's work vl be ; 1/40*60
  total work done is :5* 60( 1 / 40*60 ) + 5* 55 ( 1/ 40*60 )+ 5*45 ( 1/40*60 )+ 5*40 ( 1/40*60)+. . . nd so on till 5* 5 ( 1 ? 40*60 )
  now 5/ ( 40*60 ) { 60 + 55 + 50 + 45 +. . . . + 5 ) = 5/2400 [ sum of series using arithmatic progerssion n term summation formula
  we ans as 13/16. :)
• 12 years agoHelpfull: Yes(19) No(3)
• it will take 120 days to finish the work!!
  question says after every 5 days 5 people leave the work hence at the end of 40 days 20 men left,hence using chain rule 20:60::40:x
  x=(60*40)/20=120 days
• 12 years agoHelpfull: Yes(4) No(21)
• 44 days it will take for completion of whole task.
  5 days work of 60 men=1/8
  remaining 7/8 work will be completed by 55men.
  so it will take 39 days(actually 420/11)
  39+5=44
• 12 years agoHelpfull: Yes(1) No(10)
• work will not be complete as MD =2400...
  AND FOR THIS condition MD =1950
• 12 years agoHelpfull: Yes(1) No(0)
• 1 man completes 1/2400 in one day
  
  60 * 5 * 1/2400 = 300/2400
  55 * 5 * 1/2400 = 275/2400
  50 * 5 * 1/2400 = 250/2400
  45 * 5 * 1/2400 = 225/2400
  40 * 5 * 1/2400 = 200/2400
  35 * 5 * 1/2400 = 175/2400
  30 * 5 * 1/2400 = 150/2400
  25 * 5 * 1/2400 = 125/2400
  20 * 5 * 1/2400 = 100/2400
  15 * 5 * 1/2400 = 75/2400
  10 * 5 * 1/2400 = 50/2400
  5 * 5 * 1/2400 = 25/2400
  
  total amount of work done in 60 days before there are 0 workers
  1950/2400
  the job doesn't get finished
• 6 years agoHelpfull: Yes(1) No(0)
• 95 days it would take!!
• 12 years agoHelpfull: Yes(0) No(9)
• work will be compete in 13 days
  5 days together, then remain 1/8work in 8 days
• 12 years agoHelpfull: Yes(0) No(7)
• ans is 60 days....
  solution:
  on the first day 60 men will be der.
  so...day men
  1 60
  2 55
  3 50
  . .
  . .
  60 0
  
  
• 12 years agoHelpfull: Yes(0) No(0)
• 60*40 men can do complete work in 1 day
  1 man's 1 day's work= 1/2400
  60 men's 5 day's work = (1/2400)*5 = 1/480
  remaining work = [1-(1/480)]= 479/480
  now men left are 55
  55 men's 1 day's work = 55/2400 =11/480
  so 11/480 work is done by them in 1 day
  therefore 479/480 will be done by them in (479/480)*(480/11)= 479/11
  
  
• 12 years agoHelpfull: Yes(0) No(0)
• work will not be completed since for every five day five people are leaving so pending will be 1950 out of 2400
• 6 years agoHelpfull: Yes(0) No(0)
• work will not be completed because ;total work= 60*40=2400
  first 5 work=5*60=300
  2 nd5 work=5*55=275
  3 rd work =5*50=250
  4th work=5*45=225
  5,,,,,,,,,,,,,,=5*40=200
  6th'''''''''''''=5*35=175
  7th''''''''''''=5*30=150
  8th'''''''''''''=5*25=125
  9th'''''''''''''=5*20=100
  10th''''''''''''=5*15=75
  11th'''''''''''''=5*10=50
  12th'''''''''''''=5*5=25
  13th''''''''''''''=5*0=0
  total=1950 work;
  and total work=2400 sothat work not be completed
• 6 years agoHelpfull: Yes(0) No(0)