40) 3 dice are rolled. What is the probability that you will get the sum of the no’s as 10

• total events = 6*6*6=216
  possible cases for sum equal to 10 are
  (1,3,6)-6 combinations
  (1,4,5)-6 combinations
  (2,3,5)-6 combinations
  (2,4,4)-3 combinations
  (3,3,4)-3 combinations
  (2,2,6)-3 combinations
  so total combinations are 27
  so probability will be 27/216 = 1/8
• 12 years agoHelpfull: Yes(53) No(1)
• total no of sample space = 6*6*6=216
  now,when 3 dice are rolled then to make sum 10 ,there are events like :
  if 1 from 1st dice is chosen then only combination that can be chosen is 3 from 2nd dice and 6 from 3ed dice as 1+3+6=10 and so on 1+4+5,1+5+4,1+6+3 so that total 4 events if we choose 1 from 1st dice ,and similarly to 5 events if choose 2nd from 1st dice and so on 6 , 5 ,4 ,3..so total no of events =4+5+6+5+4+3=27
  so probability= 27/216=.125
• 12 years agoHelpfull: Yes(10) No(0)
• M really sorry fr the mistake in the above sol.this is the correct sol.
  
  (1,1,1) (1,1,2) (1,1,3) (1,1,4) (1,1,5) (1,1,6)
  (1,2,1) (1,2,2) (1,2,3) (1,2,4) (1,2,5) (1,2,6)
  (1,3,1) (1,3,2) (1,3,3) (1,3,4) (1,3,5) (1,3,6)
  (1,4,1) (1,4,2) (1,4,3) (1,4,4) (1,4,5) (1,4,6)
  (1,5,1) (1,5,2) (1,5,3) (1,5,4) (1,5,5) (1,5,6)
  (1,6,1) (1,6,2) (1,6,3) (1,6,4) (1,6,5) (1,6,6)
  (2,1,1) (2,1,2) (2,1,3) (2,1,4) (2,1,5) (2,1,6)
  (2,2,1) (2,2,2) (2,2,3) (2,2,4) (2,2,5) (2,2,6)
  (2,3,1) (2,3,2) (2,3,3) (2,3,4) (2,3,5) (2,3,6)
  (2,4,1) (2,4,2) (2,4,3) (2,4,4) (2,4,5) (2,4,6)
  (2,5,1) (2,5,2) (2,5,3) (2,5,4) (2,5,5) (2,5,6)
  (2,6,1) (2,6,2) (2,6,3) (2,6,4) (2,6,5) (2,6,6)
  (3,1,1) (3,1,2) (3,1,3) (3,1,4) (3,1,5) (3,1,6)
  (3,2,1) (3,2,2) (3,2,3) (3,2,4) (3,2,5) (3,2,6)
  (3,3,1) (3,3,2) (3,3,3) (3,3,4) (3,3,5) (3,3,6)
  (3,4,1) (3,4,2) (3,4,3) (3,4,4) (3,4,5) (3,4,6)
  (3,5,1) (3,5,2) (3,5,3) (3,5,4) (3,5,5) (3,5,6)
  (3,6,1) (3,6,2) (3,6,3) (3,6,4) (3,6,5) (3,6,6)
  (4,1,1) (4,1,2) (4,1,3) (4,1,4) (4,1,5) (4,1,6)
  (4,2,1) (4,2,2) (4,2,3) (4,2,4) (4,2,5) (4,2,6)
  (4,3,1) (4,3,2) (4,3,3) (4,3,4) (4,3,5) (4,3,6)
  (4,4,1) (4,4,2) (4,4,3) (4,4,4) (4,4,5) (4,4,6)
  (4,5,1) (4,5,2) (4,5,3) (4,5,4) (4,5,5) (4,5,6)
  (4,6,1) (4,6,2) (4,6,3) (4,6,4) (4,6,5) (4,6,6)
  (5,1,1) (5,1,2) (5,1,3) (5,1,4) (5,1,5) (5,1,6)
  (5,2,1) (5,2,2) (5,2,3) (5,2,4) (5,2,5) (5,2,6)
  (5,3,1) (5,3,2) (5,3,3) (5,3,4) (5,3,5) (5,3,6)
  (5,4,1) (5,4,2) (5,4,3) (5,4,4) (5,4,5) (5,4,6)
  (5,5,1) (5,5,2) (5,5,3) (5,5,4) (5,5,5) (5,5,6)
  (5,6,1) (5,6,2) (5,6,3) (5,6,4) (5,6,5) (5,6,6)
  (6,1,1) (6,1,2) (6,1,3) (6,1,4) (6,1,5) (6,1,6)
  (6,2,1) (6,2,2) (6,2,3) (6,2,4) (6,2,5) (6,2,6)
  (6,3,1) (6,3,2) (6,3,3) (6,3,4) (6,3,5) (6,3,6)
  (6,4,1) (6,4,2) (6,4,3) (6,4,4) (6,4,5) (6,4,6)
  (6,5,1) (6,5,2) (6,5,3) (6,5,4) (6,5,5) (6,5,6)
  (6,6,1) (6,6,2) (6,6,3) (6,6,4) (6,6,5) (6,6,6)
  This is the sample space by which u can check the
  sum of three dices 10
  No. of fav outcomes= 27
  Total no. of outcomes=216
  so the probability is 27/216=1/8
  
• 10 years agoHelpfull: Yes(7) No(3)
• ans is 1/8,
  total no of event is 6^3=216,
  &total no of events in the sum=10 is 27,
  so 27/216=1/8
• 12 years agoHelpfull: Yes(1) No(4)
• (1,1,1) (1,1,2) (1,1,3) (1,1,4) (1,1,5) (1,1,6)
  (1,2,1) (1,2,2) (1,2,3) (1,2,4) (1,2,5) (1,2,6)
  (1,3,1) (1,3,2) (1,3,3) (1,3,4) (1,3,5) (1,3,6)
  (1,4,1) (1,4,2) (1,4,3) (1,4,4) (1,4,5) (1,4,6)
  (1,5,1) (1,5,2) (1,5,3) (1,5,4) (1,5,5) (1,5,6)
  (1,6,1) (1,6,2) (1,6,3) (1,6,4) (1,6,5) (1,6,6)
  (2,1,1) (2,1,2) (2,1,3) (2,1,4) (2,1,5) (2,1,6)
  (2,2,1) (2,2,2) (2,2,3) (2,2,4) (2,2,5) (2,2,6)
  (2,3,1) (2,3,2) (2,3,3) (2,3,4) (2,3,5) (2,3,6)
  (2,4,1) (2,4,2) (2,4,3) (2,4,4) (2,4,5) (2,4,6)
  (2,5,1) (2,5,2) (2,5,3) (2,5,4) (2,5,5) (2,5,6)
  (2,6,1) (2,6,2) (2,6,3) (2,6,4) (2,6,5) (2,6,6)
  (3,1,1) (3,1,2) (3,1,3) (3,1,4) (3,1,5) (3,1,6)
  (3,2,1) (3,2,2) (3,2,3) (3,2,4) (3,2,5) (3,2,6)
  (3,3,1) (3,3,2) (3,3,3) (3,3,4) (3,3,5) (3,3,6)
  (3,4,1) (3,4,2) (3,4,3) (3,4,4) (3,4,5) (3,4,6)
  (3,5,1) (3,5,2) (3,5,3) (3,5,4) (3,5,5) (3,5,6)
  (3,6,1) (3,6,2) (3,6,3) (3,6,4) (3,6,5) (3,6,6)
  (4,1,1) (4,1,2) (4,1,3) (4,1,4) (4,1,5) (4,1,6)
  (4,2,1) (4,2,2) (4,2,3) (4,2,4) (4,2,5) (4,2,6)
  (4,3,1) (4,3,2) (4,3,3) (4,3,4) (4,3,5) (4,3,6)
  (4,4,1) (4,4,2) (4,4,3) (4,4,4) (4,4,5) (4,4,6)
  (4,5,1) (4,5,2) (4,5,3) (4,5,4) (4,5,5) (4,5,6)
  (4,6,1) (4,6,2) (4,6,3) (4,6,4) (4,6,5) (4,6,6)
  (5,1,1) (5,1,2) (5,1,3) (5,1,4) (5,1,5) (5,1,6)
  (5,2,1) (5,2,2) (5,2,3) (5,2,4) (5,2,5) (5,2,6)
  (5,3,1) (5,3,2) (5,3,3) (5,3,4) (5,3,5) (5,3,6)
  (5,4,1) (5,4,2) (5,4,3) (5,4,4) (5,4,5) (5,4,6)
  (5,5,1) (5,5,2) (5,5,3) (5,5,4) (5,5,5) (5,5,6)
  (5,6,1) (5,6,2) (5,6,3) (5,6,4) (5,6,5) (5,6,6)
  (6,1,1) (6,1,2) (6,1,3) (6,1,4) (6,1,5) (6,1,6)
  (6,2,1) (6,2,2) (6,2,3) (6,2,4) (6,2,5) (6,2,6)
  (6,3,1) (6,3,2) (6,3,3) (6,3,4) (6,3,5) (6,3,6)
  (6,4,1) (6,4,2) (6,4,3) (6,4,4) (6,4,5) (6,4,6)
  (6,5,1) (6,5,2) (6,5,3) (6,5,4) (6,5,5) (6,5,6)
  (6,6,1) (6,6,2) (6,6,3) (6,6,4) (6,6,5) (6,6,6)
  
  
  This is the sample space by which u can check the sum of three dices 10
  No. of fav outcomes= 24
  Total no. of outcomes=216
  so the probability is 24/216=1/9
• 10 years agoHelpfull: Yes(1) No(3)
• ans is 27/216.
  
• 9 years agoHelpfull: Yes(1) No(0)
• ans 13/72
  3dice roll=6*6*6
  no of 10 in dice roll=26
• 12 years agoHelpfull: Yes(0) No(13)
• 1/6 as (1,3,6) can have 6 ways ...(1,4,5) have 6 way similarly (2,3,5),(2,4,4)(2,2,6),(3,3,4)..so fav condition =36&total =216 so 36/216 =1/6
  
• 12 years agoHelpfull: Yes(0) No(2)
• satyajeet your answer is wrong.. you see there is 27 outcomes only. not 24.. so 1/8 is the answer
• 9 years agoHelpfull: Yes(0) No(0)
• ans is 27/216
• 8 years agoHelpfull: Yes(0) No(0)
• total events = 6*6*6=216
  possible cases for sum equal to 10 are
  (1,3,6)-6 combinations
  (1,4,5)-6 combinations
  (2,3,5)-6 combinations
  (2,4,4)-3 combinations
  (3,3,4)-3 combinations
  (2,2,6)-3 combinations
  so total combinations are 27
  so probability will be 27/216 = 1/8
• 8 years agoHelpfull: Yes(0) No(0)