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1.How many 6 digits nos can be formed with the digits 1,2,3,4,5,6,7 with no repetition n with an even no always in the 2nd last position?
Read Solution (Total 11)
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- 6 5 4 3 3 2
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5th position-(2, 4, 6)=6*5*4*3*3*2=2160
- 12 years agoHelpfull: Yes(52) No(2)
- becoz there are three even no. 2 4 6
hence remain other 6 no. now we select any five no. from 6 by 6p5=720
now total way 3*720=2160 - 12 years agoHelpfull: Yes(17) No(0)
- yup answer is 2160
- 12 years agoHelpfull: Yes(7) No(0)
- Ans. 2160
- 12 years agoHelpfull: Yes(6) No(2)
- Well i think you all are incorrect becoz incase if start from the 6 position, even number can come at 6,5,4,3 positon also and repitition is not allowed so better start from unit place
unit digit filled by (2,4,6)= 3 ways
ten's=remaining 2 ways
now 2 out of 7 are used, 3rd position=5 ways
4th= 4 ways
5th= 3 ways
6th= 2 ways
answer= 3*2*5*4*3*2= 720 - 12 years agoHelpfull: Yes(2) No(14)
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e e
5 4 3 2 3 2 so correct ans is 720(plz note that digits should not repeat)so it cant be 6 in first in position one after filling 2 digits in last two places so
5*4*3*2*3*2=720 - 12 years agoHelpfull: Yes(2) No(4)
- How? Please Explain ....
- 12 years agoHelpfull: Yes(1) No(0)
- bcoz there are three even no. (2, 4, 6)
hence remain other 6 no. now we select any five no. from 6 by:-
6p5=720
now total way 3*720=2160. - 12 years agoHelpfull: Yes(1) No(2)
- for the 5th position we can choose one digit for remaining four odd numbers so 4c1........the sequence s 6c1,5c1,4c1,3c1,4c1,2c1 which is equal to 6*5*4*3*4*2=2880...
- 12 years agoHelpfull: Yes(0) No(11)
- plzz xplain??
- 12 years agoHelpfull: Yes(0) No(0)
- pls expalin me d ans... as even no can be only at d last 2nd position so at 1st place there may be only 4 possible ways... m i right ???? pls solve it
- 12 years agoHelpfull: Yes(0) No(0)
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