the diagonal of the square is twice the side of equilateral triangle the ratio of area of the triangle to the area of square is?

• let side of square is a
  then diagonal of square is {sqrt2a}
  given {sqrt2a}= 2*side of triangle
  so side of triangle = {sqrt2a}/2 i.e a/sqrt2
  area of triangle = sqrt3/4*side^2......according to formula
  new area = sqrt3/4*{a/sqrt2}*{a/sqrt2} i.e.........sqrt3a*a/8
  area of square = a^2
  ratio = sqrt3*a^2/8a^2....i.e sqrt3/8
• 12 years agoHelpfull: Yes(28) No(1)
• let side of square is (a) than
  diagonal of square is (a root2)
  
  side of triangle is (a root2)/2
  
  areaof triangle/area of square
  
  area of triangle=(root3/4)*square a =(root3/8)*square a
  area of square== a*a
  
  ans is root3/8
• 12 years agoHelpfull: Yes(1) No(1)