when all the possible arrangements of the letters of word MASTER are arranged in alphabetical order. what will be the 49th word?

• AREMST
  ae_ _ _ _=24 ways
  am_ _ _ _=24 ways
  next word is aremst
• 12 years agoHelpfull: Yes(32) No(2)
• sry guys.. my solution is wrong
  AREMST is the correct. ans.
• 12 years agoHelpfull: Yes(7) No(0)
• alphbetically means starting arranging with a then e then m
  now words with starting a has !5 ways =120ways
  so take two letters
  now words with ae =!4 ways =24
  now words with am=24 ways
  total=48
  so 49 words will be "aremst"
  still total
• 12 years agoHelpfull: Yes(5) No(0)
• ASMETR
  ae_ _ _ _=4*3*2*1 = 24 ways
  ame_ _ _ = 3*2*1 = 6 ways
  amre_ _ = 2*1 = 2 ways
  are_ _ _ =3*2*1 = 6 ways
  arme _ _= 2*1 = 2 ways
  ase_ _ _ = 3*2*1 = 6 ways
  asme_ _ = 2*1 = 2 ways
  total words arranged = 24+6+2+6+2+6+2 = 48
  hence, 48th word = asmert
  therefore, 49th word = asmetr ans.
• 12 years agoHelpfull: Yes(3) No(26)
• words with ma will be24
  with me will be 24
  =48
  thus 49th wrd will start frm ms nd rest of the alphabets will be in alphabetical order...
  
  MSAETR
• 12 years agoHelpfull: Yes(0) No(8)
• AREMST
  AE_ _ _ _ =4!
  AM _ _ _ _ =4!
  AREMST =49 th word
• 5 years agoHelpfull: Yes(0) No(0)