the first 44 positive integers are written in the order to form the largest number n=123456789101111213..424344. what will be the remainder when n is divided by 45?

• no will be div by 45 when it is divided y both 9 and 5
  a no is div by 9 if sum of digits is div by 9
  now sum of digits of given no is 270
  so the no is div by 9
  and since last digit is 4 when div by 5 it leaves rem 4
  let us say numbers such as 9,54...
  we see they are div by 9 but leaves rem 4 when div by 5..
  so when div by 45 they leave rem 9
  so req ans=9
  
• 12 years agoHelpfull: Yes(23) No(8)
• 45 can be written as 9*5 .so chek the dividiblity rule for both 9 and 5..
  and hence ans is 4
• 12 years agoHelpfull: Yes(7) No(5)
• plz confirm that is it 4 or 9?? both are in the options
• 12 years agoHelpfull: Yes(4) No(0)
• can u guys pls mention options also.................
  
• 12 years agoHelpfull: Yes(0) No(0)
• abishek grover how can you find the remqainder 9 ............'pls explain clearly
  and if you have 81 tcs pattern then pls send yaar on abhi1991002@gmail.com
• 12 years agoHelpfull: Yes(0) No(1)
• please give the shortcut to find sum of digits... to get 270
• 9 years agoHelpfull: Yes(0) No(0)