what is the ramainder when 50! is divided by 47*47

• the ans will be 1927...
  50! can be written as 50*48*47*46!*49/47*47
  50*48*49*(47-1)!/47
  and (n-1)!/n=-1
  so reminder when 47 is divided by 50 is 3,by 48 is 1 and by 49 is 2 and by (47-1)! is -1
  so total is -6
  and +ve reminder is 41
  and we have to multiply it by 47 becoz first we cut it
  so final ans is 41*47=1927
• 12 years agoHelpfull: Yes(22) No(7)
• Ans: 8
  =50*49*48*47*46!/47*47
  =50*49*48*46!/47
  apply wilson thm
  46!mod47 =-1
  so 50*49*48*46!mod47
  taking 50 -> -1
  49 -> -2
  48 -> -3
  so (-1)(-2)(-3)46! mod 47 = -1
  6* 46! mod 47 =1
  6 * x mod 47 =1
  i.e what shud be multiplied to 6 to get 1 as remainder,,
  6*8=48
  thus simply remaindr is 8
• 12 years agoHelpfull: Yes(4) No(8)
• 0 will be remainder
• 12 years agoHelpfull: Yes(2) No(3)
• ans should be 1927
• 12 years agoHelpfull: Yes(1) No(2)
• ans is 41
  50!/(47 x 47)=(50 x 49 x 48 x 46!)/47
  
• 11 years agoHelpfull: Yes(1) No(0)
• ans is 41
  50!/(47 x 47)=(50 x 49 x 48 x 46!)/47
  
• 11 years agoHelpfull: Yes(1) No(0)
• Since 50! would have 0 at its units place and (47*47)would have 9 at its units place, thus dividing 50! by (47*47) would provide 9 as remainder.
• 12 years agoHelpfull: Yes(0) No(29)
• reminder will be 0
• 12 years agoHelpfull: Yes(0) No(1)
• remainder is 43......
• 12 years agoHelpfull: Yes(0) No(4)
• i think ans is 3...
• 12 years agoHelpfull: Yes(0) No(4)
• the last digit of 50! is 0 and last digit of 47*47 is 9 so divisible by last digit 9 in 0 then remainder is 1
• 11 years agoHelpfull: Yes(0) No(0)