A,B and C can do a piece of work alone in 15 , 25 and 40 days respectively.They start together but B left the work as soon as the work was half completed and c left the work when it was 3/4th completed. A doing the remaining work alone. In how many days the work completed?

• ans 300/79+30/11+15/4=10.2747 days
• 12 years agoHelpfull: Yes(30) No(3)
• ans will be 10.2742 days
• 12 years agoHelpfull: Yes(7) No(1)
• 9.85 days...say nearly 10 days...madhavi...is it correct ???
• 12 years agoHelpfull: Yes(4) No(7)
• 8.5486 say 8.55 days.
  total days = 300/79+30/11 + 15/4= 8.5486 days
• 12 years agoHelpfull: Yes(2) No(7)
• its coming out to be 9.49 i.e. on 10th day work will be completed.
• 12 years agoHelpfull: Yes(2) No(10)
• 10.27 is correct answer................
• 12 years agoHelpfull: Yes(2) No(0)
• pls explain the method... how it is solved?
• 12 years agoHelpfull: Yes(1) No(0)
• plz mail me tcs new pattern paper akritigupta.2009@gmail.com
• 12 years agoHelpfull: Yes(0) No(3)
• ans:9.57 days
  Take the L.C.M of 15,25,40 i.e 600 (assume this as total quantity of work to be done)
  A completes 600/15= 40 units/day
  B -> 600/25 =24
  C-> 600/40=15
  A+B+C together completes 79 units of work per day
  Now, 300/79+( 150/(15+40))+150/40 =9.75 days approximately
• 11 years agoHelpfull: Yes(0) No(0)