Given, a(i) = a(i-1)+a(i-2) where i>=3
Now if a10=322 then what is the value of a5?
hints:- a10=a9+a8, a9=a8+a7 and so on

• We can solve this by using the relation as a3=a2+a1, a4=a3+a2 and the put the value of a3..... similarly upto a10 which is equal to a10=34a2+21a1 and a10=322, so by putting a1=4 and a2=7 we get the result as a5=29
  Ans:29
• 9 years agoHelpfull: Yes(4) No(1)
• ans is 29
  
• 9 years agoHelpfull: Yes(2) No(1)
• its star question in tcs .pls some one reply me
  
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• in question u should add this
  a3=2a2+a1
  
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• what is the answer for first question in part 2 analytical held on 2nd march
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• whether its a star mark question???
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• ans is 29
  
• 9 years agoHelpfull: Yes(0) No(0)