(2^74)+(2^2058)+(2^2n) is a perfect square for which value of n?
A)2010
B)2011
C)2012
D)2100

• answer is 2020. so its a dummy question.
• 11 years agoHelpfull: Yes(11) No(8)
• 2^(37*2)+2^(1029*2)+2^(n*2)
  we see that ,2's power no. is multiple of (odd no.*2)
  thats why.....'n' must be odd no. and only 2011 is odd no.
  ans is 2011
• 11 years agoHelpfull: Yes(10) No(10)
• (2^37)^2+(2^n)^2+2*2^n*2^37.we know that 2^n*2*2^37=2^2058.
  1+n+37=2058
  n=2058-38=2020 :)
• 11 years agoHelpfull: Yes(8) No(2)
• if 2020 is not the answer thn how v'll solve pls specify...
• 11 years agoHelpfull: Yes(1) No(0)
• For such type questions go for nearest value..ie 2012..may be
• 11 years agoHelpfull: Yes(0) No(2)