A man engaged a servant on a condn that he’ll pay Rs 40 and also give him a bag at the end of the yr. He
served for 9 months and was given a turban and Rs 55. So the price of turban is
i. Rs 10 / 29 / 0 / none

• let x be the price of the bag and y be the price of turban
  then at the end of the yr,servant will receive=RS 40+x
  therefore,at the end of 9 month he will receive=Rs(40+x)/12 * 9
  which is =55+y
  from here we get x=(100+4y)/3
  put y=2,5,8.....29... we get x=26,40,44...
  hence ans is 29!!
• 12 years agoHelpfull: Yes(7) No(32)
• wrong question. Because there are two variable as consider y for turban and x for bag. To solve for this we should have minimum two relations, here only one relation exists.
• 5 years agoHelpfull: Yes(0) No(1)
• Answer is 29 by using trail and error method
• 5 years agoHelpfull: Yes(0) No(1)
• 12m=40+b
  9m=55+b
  
  12m-b=40
  9m-b=55
  --------------
  3m=15
  m=5
  
  9m-s=55
  9(5)-s=55
  s=55-45
  s=10
• 5 years agoHelpfull: Yes(0) No(0)