2.How many 4 digit no. can b formed wit digits 1, 2, 3,4,5 which r divisible by 4 and digits not repeated
144 / 168 / 182 / none
3.. If 1= (3/4)(1+ (y/x) ) then
i. x=3y
ii. x=y/3
iii. x=(2/3)y
iv. none

• last 2 digits can be 12,24,32,52 only.
  
  First two numbers can be any two numbers of balance 3 numbers available.
  
  so number of possible nos = 4*3*2 = 24
• 12 years agoHelpfull: Yes(20) No(9)
• 2)a num div by 4 means last two digits should be either 12,24,32,52 which is possible in 4 ways. remaining 2 digits can be filled with remaining 3 digits in 6 ways.so,6*4=24 is the ans.
  
  3)1=3/4(1+x/y)
  x=3/4(x+y)
  4x=3x+3y
  x=3y
  so option i
• 12 years agoHelpfull: Yes(7) No(1)
• possible no's for last 2 digits are 12,24,32,52
  so last 2 digits can be filled in 4! ways= 24 ways
  now remaing 2 places can be filled in 3P2 ways= 3!=6
  therefore final answer is = 6*24=144
• 12 years agoHelpfull: Yes(5) No(14)
• 24 is d answer
  
• 12 years agoHelpfull: Yes(3) No(2)
• 1.none
  2.i i.e x=3y
• 8 years agoHelpfull: Yes(3) No(1)
• last tow digits make constent
  now 2 place remaining
  5 digit can arrang in 2 place with out repeat 2^4
  now only 12 n 24 can be at last place so ans will be
  2*2^4
• 12 years agoHelpfull: Yes(1) No(1)
• The condition for any number to be divisible by 4 is that the last two digits taken together must be a multiple of 4
  The digits given are - 1,2,3,4,.5
  Now the last two digits must be a multiple of 4
  There are 4 cases : 12 , 24 , 32 , 52 . So if the last two digits are these numbers then the five digit number formed would be divisible by 4
  
  (a) If the last two digits are 12 , then the remaining 2 places can be filled in 2! ways
  (b) if the last two digits are 24 , then the remaining 2 places can be filled in 2! ways
  (c) if the last two digits are 32 , then the remaining 2 places can be filled in 2! ways
  (d) if the last two digits are 52 , then the remaining 2 places can be filled in 2! ways
  
  Total numbers which are divisible by 4 = 4*2!=8
• 12 years agoHelpfull: Yes(1) No(8)
• If x=3y,then
  1=(3/4)[1+(y/x)]
  1=(3/4)(1+y/3y)
  1=(3/4)(1+1/3)
  1=(3/4)(4/3)
  1=1
  Hence ans is 3y
• 8 years agoHelpfull: Yes(1) No(0)
• ending 2 digits can be 12,24,32,52
  fixing last two digits one by one
  12-->3*2*1*1=6
  24-->3*2*1*1=6
  32-->3*2*1*1=6
  52-->3*2*1*1=6
  6+6+6+6=24
  answer=24
• 7 years agoHelpfull: Yes(1) No(0)
• 4digit numbers=3!*2C1=12
• 12 years agoHelpfull: Yes(0) No(5)
• hiii this is good answer
  
  
  
  
  
  
  
  
  
• 8 years agoHelpfull: Yes(0) No(1)