Q1.One day when Ram was walking on the street, one boy requested him to donate for cancer patients welfare fund. He gave him a rupee more than half the money he had. He walked a few more steps. Then came a girl who requested him to donate for poor people's fund for which he gave two rupees more than half the money he had then. After that, again a boy approached him for an orphanage fund. He gave three rupees more than half of what he had. At last he had just one rupee remaining in his hand.
How much amount did Ram have in his pocket when he started?
a)Rs.72 b)Rs.58 c)Rs.35 d)Rs.42

• assume total money =x
  remaining money after 1st donationan=(x-2)/2
  " " " 2nd " ={(x-2)/2}-[{(x-2)/4}+2]=(x-10)/4
  " " " 3rd " ={(x-10)/4}-[{(x-10)/8}+3]=(x-34)/8
  a/c to Q
  (x-34)/8=1
  hence x= Rs 42 . Ans=(d)
• 12 years agoHelpfull: Yes(18) No(0)
• 42 go with option it is more easier :)
• 12 years agoHelpfull: Yes(8) No(2)
• (((1+3)2+2)2+1)2=42
• 10 years agoHelpfull: Yes(2) No(0)
• Last he had 1rupee,when he gave to boy 3 rupees more than half so it written as (1+3)*2 similarly remaing i.e. (((1+3)2+2)2+1)2=42
• 10 years agoHelpfull: Yes(2) No(0)
• 42.
  solve thru options
• 12 years agoHelpfull: Yes(1) No(0)
• Last he had 1rupee,when he gave to boy 3 rupees more than half so it written as (1+3)*2 .then girl had came asked
  fund then 2rupees more than half he had so ((1+3)*2+2)*2).and again boy asked fund then a rupee more than half.so
  ((1+3)*2+2)*2+1)*2)) =42.
  
• 10 years agoHelpfull: Yes(1) No(0)
• hai sumit could u explain me detail
• 12 years agoHelpfull: Yes(0) No(2)
• 42 solve using option
  
• 10 years agoHelpfull: Yes(0) No(0)
• Last he had 1rupee,when he gave to boy 3 rupees more than half so it written as (1+3)*2 similarly remaing i.e. (((1+3)2+2)2+1)2=42
• 10 years agoHelpfull: Yes(0) No(0)