A certain party consists of four different group of people - 30 students, 35 politicians, 20 actors and 27 leaders. On a particular function day, the total cost spent on party members was Rs.9000. It was found that 6 students spent as much as 7 politicians, 15 politicians spent as much as 12 actors and 10 actors spent as much as 9 leaders. How much did students spent?

• as question says,
  30s+35p=20a+27L =9000 say eqn 1
  6s=7p , 15p=12a , 10a=9L
  or
  6s=7p , 7p=(12*7)/15 a =(28/5)a , (28/5)a= (28/50)*9L
  OR
  6s=7p=(28/5)a=(252/50)L = K
  now
  
  s=(k/6), p= (k/7) , a=(.1785k) , L=(.1984k)
  put these value in eqn one you will got value of k is 475.511
  now 6s=k
  hence s=k/6=79.25
  there are 30 students hence 79.25*30=2377.55
• 11 years agoHelpfull: Yes(26) No(6)
• thnkx swati :)
• 11 years agoHelpfull: Yes(5) No(1)
• hai swati can you explain this problem once again?how 28/5 came
• 11 years agoHelpfull: Yes(4) No(1)
• sry sweta eqn one is 30s+35p+20a+27L = 9000
• 11 years agoHelpfull: Yes(3) No(1)
• Solution:
  
  Let S be the amount spent for all students
  Let P be the amount spent for all politicians
  Let A be the amount spent for all actors and
  Let L be the amount spent for all leaders.
  given that 6 students spent as much as 7 politicians
  
  i.e Amount spent per student x 6 = Amount spent per politician x 7
  Or (Total amount spent on students / Total Students) x 6 = (Total amount spent on politicians / Total politicians)x 7
  Or., (S/30)x 6 = (P/35)x7
  => S/5 = P/5
  
  => S = P ..... eqn 1
  
  15 politicians spent as much as 12 actors :
  Therefore, (P/35)x15 = (A/20)x12
  => 3P/7 = 3A/5
  => 5P = 7P
  => 5S = 7A (since S = P)
  
  => A = 5S/7 ........eqn2
  
  and 10 actors spent as much as 9 leaders :
  Therefore, (A/20)x10 = (L/27)x9
  => 3A = 2L
  => A = 2L/3
  => 5S/7 = 2L/3 (since A=5S/7)
  
  => L = 15S/14 ......eqn3
  
  the total amount spent for the party is Rs.9000
  i.e., S+P+A+L = 9000
  from eqn1, eqn2, eqn3 we have
  S + S + 5S/7 + 15S/14 = 9000
  53S/14 = 9000
  s=9000*14 / 53
  s=2290.90 ~ 2291
  
  Hence the answer is Rs.2291
• 10 years agoHelpfull: Yes(2) No(2)
• Let S be the amount spent for all students
  Let P be the amount spent for all politicians
  Let A be the amount spent for all actors and
  Let L be the amount spent for all leaders.
  given that 6 students spent as much as 7 politicians
  
  i.e Amount spent per student x 6 = Amount spent per politician x 7
  Or (Total amount spent on students / Total Students) x 6 = (Total amount spent on politicians / Total politicians)x 7
  Or., (S/30)x 6 = (P/35)x7
  => S/5 = P/5
  
  => S = P ..... eqn 1
  
  15 politicians spent as much as 12 actors :
  Therefore, (P/35)x15 = (A/20)x12
  => 3P/7 = 3A/5
  => 5P = 7P
  => 5S = 7A (since S = P)
  
  => A = 5S/7 ........eqn2
  
  and 10 actors spent as much as 9 leaders :
  Therefore, (A/20)x10 = (L/27)x9
  => 3A = 2L
  => A = 2L/3
  => 5S/7 = 2L/3 (since A=5S/7)
  
  => L = 15S/14 ......eqn3
  
  the total amount spent for the party is Rs.9000
  i.e., S+P+A+L = 9000
  from eqn1, eqn2, eqn3 we have
  S + S + 5S/7 + 15S/14 = 9000
  53S/14 = 9000
  s=9000*14 / 53
  s=2290.90 ~ 2291
  
  Hence the answer is Rs.2291
• 7 years agoHelpfull: Yes(0) No(0)