if a b c d e are integer in increasing order n a b c d e FG FG can

ans is b.) 5
if we take five numbers as...18,19,20,21,22...their sum is 100...bt FG is two digit...so the no. are 17,18,19, 20, 21...which gives sum as 95..
95= 10*9 + 5..so max values of G is 5
12 years agoHelpfull: Yes(8) No(11)
b)5
if we take 1,2,3,4,5 as a,b,c,d,e
then a+b+c+d+e=15 I.E. f=1 n g=5
10f+g=10(1)+5=15
so max val of g is 5 for any value of a,b,c,d,e
12 years agoHelpfull: Yes(2) No(2)
9+7+6+5+4=31
so value of G=1
12 years agoHelpfull: Yes(1) No(7)
Ans=b)5
if we take 1,2,3,4,5 as a,b,c,d,e
then a+b+c+d+e=15 I.E. f=1 n g=5
10f+g=10(1)+5=15
so max val of g is 5 for any value of a,b,c,d,e
12 years agoHelpfull: Yes(0) No(8)
when we take 5 consecutive nos. unit place of summation is either 0 or 5.so ans is 5...for more xplanation see parag's exmple.
12 years agoHelpfull: Yes(0) No(3)
all digit(a to g) must be different .. 4+5+6+8+9=32 g=2
12 years agoHelpfull: Yes(0) No(0)
10*5(F)+5(G)=55(FG)
so, G=5
12 years agoHelpfull: Yes(0) No(0)

if a,b,c,d,e are integer in increasing order n a+b+c+d+e=FG,FG can be written as 10F+G then what is the max. value of G.
a)4
b)5
c)3