TCS
Company
HR Interview
Interview
Weight of M,D and I is 74.Sum of D and I is 46 greater than M.I is 60% lessthan D.what is D weight
Read Solution (Total 17)
-
- m+d+i=74
d+i=m+46
From above m=14
d-60/100d=i ie 2/5d=i
therefore; from above
d+i=60
d+2/5d=60
d=42.9
- 12 years agoHelpfull: Yes(58) No(9)
- m+d+i=74..........1
let m=x
d+i=x+m
from 1 x+46+x=74
2x=28
x=14
now
let d=y
i is 60 % less than d
there fore i =40y/100
d+i=x+46
x=14
d=y
i=40y/100
substitute ol value y=43 approx - 12 years agoHelpfull: Yes(22) No(5)
- 10 years
M+D+I=74
D+I+46=M
Let age of D be D then, I=0.4D
Solving these eq we get D=10,I=4 & M=60 - 12 years agoHelpfull: Yes(14) No(38)
- Given m+d+i=74----------------------------------(1)
d+i+46=m==>>d+i=m-46----------------------(2)
i=0.4d----------------------------(3)
solving 1 and 2 results in the value of m=60
sub m=60 in 1 we get d+i=14------(4)
solving 3 and 4 gives d=10 and i=4
- 12 years agoHelpfull: Yes(9) No(5)
- m + d + i = 74 ------------ (1)
d + i = m + 46 ------------ (2)
putting value of d + i from equation 2 in equation 1
=>m + m + 46 = 74
=>2m = 28
=>m = 14
According to question
d - (d*60/100) = i
=>d - (3d/5) = i
=>5d-3d = 5i
=>2d = 5i
=> i = 2d/5 -------- 3
putting value of i and m in equation 2
d + 2d/5 = 46 + 14
7d = 60 * 5 = 300
d = 300/7 = 42.85 - 12 years agoHelpfull: Yes(8) No(3)
- M+D+I=74
D+I=M+46
0.4D=I
Solving,
D + 0.4D=M+46
1.4D=M+46.....(1)
M+D+0.4D=74
M+1.4D=74........(2)
adding (1) and (2)
2.8D=46+74
Hence, D=120/2.8
- 12 years agoHelpfull: Yes(5) No(3)
- Ans=10 years
M+D+I=74
D+I+46=M
Let age of D be D then, I=0.4D
Solving these eq we get D=10,I=4 & M=60
this is correctttttttttttttttttttt. - 12 years agoHelpfull: Yes(4) No(16)
- m+d+i=74
d+i+46=m..........(1)
i=0.4d
m=1.4d+46
put it in equn 1
d=10
- 12 years agoHelpfull: Yes(3) No(5)
- 42.85 is correct
- 12 years agoHelpfull: Yes(3) No(3)
- bt how dis possible that d=10..
when it is given in question that sum of d and i is 46 greater than m??
then the eq. d+i+46= m; is wrong.... - 10 years agoHelpfull: Yes(3) No(1)
- M+D+I=74
D+I=46+M
I=0.4D
Solving these eq we get D=85.7 - 12 years agoHelpfull: Yes(1) No(18)
- M+D+I=74 ....1
M+I-M=46 ....2
I=D(1-60%)= 0.4D ...3
Putting value of I by EQ 3 in EQ 1
We get
M+1.4D=74 ...4
& in EQ 2
We get
1.4D-M=46 ...5
On Adding eq 4&5 we get
D=50. - 12 years agoHelpfull: Yes(1) No(9)
- Ans: 10
M + D + I = 74 ⇒ M = 74 -D - I
M = D + I + 46
I = 410 D
74 - D - I = D + I + 46
74 - D - 410 D = D + 410 D + 46
⇒ D = 10
- 10 years agoHelpfull: Yes(1) No(3)
- M + D + I=74 ----------(EQN 1)
D + I =M + 46 ----------(EQN 2)
FROM EQN 1 & 2
2(D+I)=120
D+I=60 ----------(EQN 3)
ALSO
I=D-(D*6)/10
=>I=7D/5 (PUT THIS IN EQM 3)
WE GET
D=42.8 - 9 years agoHelpfull: Yes(1) No(0)
- Explain d+2/5d part in 1st solution
- 9 years agoHelpfull: Yes(0) No(0)
- How d+i+46=m possible?
It's clearly mentioned in question Sum of D and I is 46 greater than M - 9 years agoHelpfull: Yes(0) No(0)
- those who got d=10 how the f**k is m=d+i+46
- 9 years agoHelpfull: Yes(0) No(0)
TCS Other Question