Father is 5 times faster than son. Father completes work in 40days before son.If both of them work together when will work get complete?

• sol is if son takes 5x days, father wil take x days.thus 4x is the difference in days which is equal to 40.therefore,x=10
  and 5x=50
  thus the work is done together in 50/6 days
  
• 12 years agoHelpfull: Yes(89) No(4)
• let takes x days TO COMPLETE THE WORK than father will take x-40
  
  as we know time is inversely propotional to speed so
  time=1/speed
  
  fatherstime/sonstime
  
  x-40/x
  
  and given that speed ration btwn father and son is 5:1
  
  so x-40/x=5/1
  x-40=5x
  4x=40
  x=10
  so if father and son work together than
  
  1/10+1/50
  25/3 days is ans
  
  
• 12 years agoHelpfull: Yes(17) No(9)
• 1/x = son
  5*(1/x) = father
  
  according to question-->
  5/x = 1/(x-40)
  on solving x=50
  so => 1/x + 5/x
  => 1/50 + 5/50
  => 6/50
  means 50/6 days
  
  
• 12 years agoHelpfull: Yes(9) No(1)
• 50/6 is answer
  
  if father work 5
  then son 1
  and if son done in 50 days
  father done that work in 1o days
  so total ratio is 6 then
  work for 50days -> 50/6
• 12 years agoHelpfull: Yes(6) No(2)
• let son work be x...
  father be 5x...
  there fore father can complete work in 40 days
  combine work be x+5x....
  
  no of days when they work combine be y
  
  so eqn.. (5x/x+5x)=(y/40)
  
  5/6 = y/40
  
  ans y=100/3
  
• 12 years agoHelpfull: Yes(5) No(17)
• answer:8(1/3)
  Time taken is inversely proportional for efficiency.
  
  Since the father is 5 times faster than the son, the time taken by the father and son to complete the work will be in the ratio 1:5.
  
  Let the no. of days be x and 5x.
  The father takes 40 days less.
  5x-x=40
  x=10
  If both of them work together,
  (10*50)/(10+50)
  = 500/60
  = 8(1/3) day
  
• 8 years agoHelpfull: Yes(5) No(0)
• let son takes 5x days, father wil take x days.
  thus 4x is the difference in days which is equal to 40.
  therefore,x=10and 5x=50
  thus the work is done together in 25/3 days.
• 12 years agoHelpfull: Yes(4) No(2)
• if son done in x days
  then father done in x/5 days
  as per given information
  x/5=40 => x=200
  therefore son efficiency is 1/160 per day
  and father efficiency is 1/40 per day
  together f+s = (1/40)+(1/160)=5/160=1/32
  therefore f+s complete in 32 days.
• 12 years agoHelpfull: Yes(3) No(19)
• Lets take whole work 1,and son do x unit work per day and father unit work per day ,
  so
  1/x +1/(5x) =40 days
  1=50x (total work)
  so 50x/(5x+x) = 8+1/3 [father 5x,son x]
• 9 years agoHelpfull: Yes(2) No(0)
• 50/6 is the wrong answer.
  
  25/3 is correct.
• 12 years agoHelpfull: Yes(1) No(13)
• father is 5 times faster than son
  if son completes 1 part then father completes 5 parts
  let son completes the work in x days
  father will complete the same work in (x-40) days.
  so (x-40)*5 = x * 1
  =>5x-200 = x
  =>4x = 200;
  =>x = 200/4 = 50
  if son completes the work in 50 days then the father will complete the same work in 40 days less, that mean in 10 days.
  per day father completes 5 parts. total work is 5*10 = 50 parts.
  per day son completes 1 part. total work is 5*1 = 5 parts.
  hence per day both father and son will complete (5 + 1)parts = 6 parts.
  so day required = 50/6 = 8.33333 days = 9days
  father
• 12 years agoHelpfull: Yes(1) No(3)
• S F F+S
  x 5x 6x
  S/F=1/5
  Ts/Tf=5/1 i.e.50/10
  S F S+F
  Time 50 10 8.33
  Rate 1 5 6
  Work 50(lcm)
  
  Ans:8.33
• 12 years agoHelpfull: Yes(0) No(1)
• if father does a work in x days, son takes 5x days.
  diff = 4x =40
  so, x=10 and 5x= 50
  in one day father does 1/10 work and son does 1/50 work.
  together (1/10 + 1/50 i.e. 6/50)
  so they will take 50/6 days i.e. 8.33 days
• 8 years agoHelpfull: Yes(0) No(1)
• x=5(x-40)
  x=50
  son complete the work in 50 days and father take 10 days for complete the work.....
  1/50+1/10=6/50 work done in 1 day if both work together..
  so 50/6 days required
  
• 8 years agoHelpfull: Yes(0) No(1)
• solution:father takes 5x and son takes x
  
• 8 years agoHelpfull: Yes(0) No(1)
• Time taken is inversely proportional for efficiency.
  
  Since the father is 5 times faster than the son, the time taken by the father and son to complete the work will be in the ratio 1:5.
  
  Let the no. of days be x and 5x.
  The father takes 40 days less.
  5x-x=40
  x=10
  If both of them work together,
  (10*50)/(10+50)
  = 500/60
  = 8(1/3) day
• 3 years agoHelpfull: Yes(0) No(0)