If x^2 + y^2 + 2x + 1=0 then what is the value of x^31+x^35?

• In the problem, x^2+2x+1 can be written as (x+1)^2 which implies (x+1)^2 + y^2 =0
  So, for sum of two squares to become 0, both must be 0, which implies:
  (x+1)^2 = 0. So x=-1, and therefore x^31+x^35 = -1 + -1 = -2
  So, the answer must be -2.
• 12 years agoHelpfull: Yes(68) No(1)
• x^2 + y^2 + 2x + 1=(x+1)^2+y^2=0
  So, x=-1
  and x^31+x^35=-1-1=-2
  
  
  
  
  
  
  
• 12 years agoHelpfull: Yes(6) No(0)
• ans is -2
  
• 12 years agoHelpfull: Yes(1) No(1)
• x^2+y^2+2x+1=0;
  it is more easy to find the values of x and y by
  (x+1)^2 +y^2=0; x=-1,y=0;
  so putting these values in x^31+x^35 it will be
  -1 + -1 = -2
  so ans is -2
  
• 12 years agoHelpfull: Yes(0) No(3)