In a 100m race , A beats B by 15m and B beats C by 10m . If A beats C by 5 sec then find the speed of C.

• When A covers 100m, B covers 85m
  When B covers 100m, C covers 90m
  When B covers 85m, C covers 76.5m
  When A covers 100m, C covers (100-76.5)=23.5m
  therefore, Speed= D/T= 23.5/5= 4.7m/s
  
• 12 years agoHelpfull: Yes(67) No(11)
• A-----15 m----B--10 m-------C
  [----------25 m-------------]
  [--------time= 5 sec--------]
  speed = D/T
  =25/5
  =5 m/s.
  Hope this is correct.
  
• 12 years agoHelpfull: Yes(47) No(56)
• when A covers 100 B covers 85
  when B covers 100 C covers 90
  i.e when B cover 1m C covers.9m
  so when B covers 85 C covers .9*85=76.5m
  i.e A cover 100 C covers 76.5, total difference=100-76.5=23.5
  speed of C is 23.5/5=4.7m/s
• 12 years agoHelpfull: Yes(45) No(3)
• A beats B by 15m and b beats c by 10m
  this means a beats c by (10+15)m and 5 sec
  so c covers 25m in 5 sec
  and 5*60m in 60 sec
  so speed of c is 300 m/min
  which is 18 km/hour
  
  
• 12 years agoHelpfull: Yes(11) No(13)
• Is it correct?????
  
  when A is at 100m B is at 85 m and when B is at 100m C is at 90
  putting them on one line C at 76.5m when A is at 100m and B is at 85m
  so A needs 5 sec to cover those 23.5 m
  speed of A=23.5/5=4.7m/s
  time taken by C-time taken by A=5sec
  
  
  d/s (of C) - d / s (of A)=5sec
  23.5/s - 23.5/4.7=5
  s=2.35m/s which is speed of C
• 12 years agoHelpfull: Yes(10) No(15)
• when A is at 100m B is at 85 m and when B is at 100m C is at 90
  putting them on one line C at 76.5m when A is at 100m and B is at 85m
  so A needs 5 sec to cover those 23.5 m
  speed of A=23.5/5=4.7m/s
  so A will cover 100m in 100/4.7=21.27s
  then C will cover in 21.27+5 sec=26.27s
  so speed of C to cover 100m in 26.27sec,,,so speed of C= 100/26.27=3.80 m/s
  ANS:3.80m/s
• 12 years agoHelpfull: Yes(9) No(5)
• speed of c= 4.7m/s
• 12 years agoHelpfull: Yes(9) No(0)
• wen A=100 B=85 & wen B=100 C=90.
  hence, wen A=100 B=85 C=76.5 (by unitary method)
  therefore,speed=dist/time
  dist(btween A & C )=100-76.5=23.5m
  sp= 23.5/5 = 4.7m/s ans!
• 12 years agoHelpfull: Yes(8) No(2)
• let speed of a = x m/s
  t= 100/x sec
  in this time b travels 85 and c travels 75 mtrs
  hence
  S=(85/100)*x
  and
  S=(75/100)*x ............................................(1)
  
  
  now again t is 5 sec more than t
  => t(C)=100/x+5
  again S can be written as distance/time
  
  => S=100/(100/x+5)..........................................(2)
  equating 1 & 2 we get x=100/15 m/sec
  hence S=5m/sec
  
  ans=5
• 12 years agoHelpfull: Yes(5) No(5)
• A beats B by 15m which means A is ahead of B by 15m at the end.
  B beats by 10m says B is ahead of C by 10m
  Totally C is 25m(10+15) behind of A and C is beaten by A by 5 sec.
  i.e.. C needs 5 sec to cover 25m
  speed=25m/5s=5m/s===>300 meters per minute
• 12 years agoHelpfull: Yes(4) No(7)
• c goes 15m in 5s
  so speed is 3m/s
• 12 years agoHelpfull: Yes(4) No(7)
• yar jab concept clear nhi hta to solution mat diya kro.it's 4.7m/s
• 12 years agoHelpfull: Yes(4) No(3)
• it is clear that A fst compltd the race. when a is at 100 mtr b must be at 85 mtr.
  nd it is given that when b is at 100 mtr c must be at 90 mtr. but when b is at 85 mtr c will be at 85*90/100 = 76.5
  now the distance they covered in same time duration is 100:85:76.5
  so now timr taken vl be irproportional to the distance travelled
  taken time's ratio will be 76.5:85:100100/85,
  speed of a,b,c is respectively :)
  difference is given in time btw a& c is 5 sec.
  equation can be summarised as : 100/(76.5x)- 100/(100X) =5sec.
  x= .0614379
  speed of c is 100/(100*.0614379)=16.27
  ans 16.27 per sec
  
• 12 years agoHelpfull: Yes(3) No(20)
• beats B by 15m means when A moves 100m B moves 85m.
  B beats C by 10m means when B moves 100m C moves 90m.
  =>when B moves 1m C moves .9m. =>when B moves 85m C moves .9*85m=76.5m.
  If A beats C by 5 sec =>c takes 5sec to moves 23.5m.
  =>c takes 1sec to moves 4.7m. =>speed=4.7m/sec
• 11 years agoHelpfull: Yes(1) No(0)
• A/B=100/(100-15)= 20/17........(1)
  B/C=100/(100-10) =10/9............(2)
  LET A beat C by y m
  so A/C=100/(100-Y)
  from (1) and (2) we get
  Y=23.5m
  so distance=speed*time
  23.5=V*5
  V=4.7m
• 9 years agoHelpfull: Yes(1) No(0)
• ratio of speed of A and B = 100/85 = 20/17
  , ratio of speed of B and C = 100/90 =10/9 -->
  ratio of speed of A and C = 20/17 * 10/9 = 200/153 = 100/76.5 ,
  A wins the race by 23.5 m ,
  after 5 sec C also reaches the end point ,
  means speed of C = 23.5 / 5 = 4.7 m/sec
• 10 years agoHelpfull: Yes(0) No(0)