A can run a kilometre in 4 min 54 sec and B in 5 min. How many metres start can A give B in a km race so that the race may end in a dead heat?

A. 25 m

B. 20 m

C. 15 m

D. 10 m

• 1 product total cost = .75+4.04+.29 = $5.08
  s.p. = $5.10
  profit of selling of 1 product = $0.02
  number of products to gain profit of $5600 = 5600/.02 = 280000
  
  answer 280000)
  
  am i right??
• 9 years agoHelpfull: Yes(42) No(9)
• A can run 1000m in 294sec
  B can run 1000m in 300sec
  i.e. B can run 10m in 3sec
  and A beat B by 6sec
  therefore A can give head start of 6sec i.e 20m.
  
• 9 years agoHelpfull: Yes(24) No(2)
• cost price=0.75+4.04+0.29=5.08
  selling price=5.10
  profit=5600
  ans=5600/(5.10-5.08)=280000
• 9 years agoHelpfull: Yes(2) No(0)
• http://www.careerbless.com/aptitude/qa/racesandgames2.php
  
  u ll get answer in this site
  
• 9 years agoHelpfull: Yes(2) No(0)
• B is delayed by 6 sec from A . B travels 20 meter in 6 sec so after 6 sec or 20 meters A has to start.
• 7 years agoHelpfull: Yes(2) No(0)
• B runs 1000mts in 5mins
  difference between A & B is 6 secs
  in 300secs if B runs 1000mts
  in 6secs B runs ---?
  (6*1000)/300=20mts
  
• 9 years agoHelpfull: Yes(1) No(0)
• any one give answer for this question?
  
• 9 years agoHelpfull: Yes(0) No(0)
• ur roght kaju gupta
  
• 9 years agoHelpfull: Yes(0) No(0)
• B runs 1000mts in 5*60secs=300secs
  How many mts does B runs in 6secs
  300secs------1000mts
  6secs--------?
  (6*1000)/300=20mts
• 9 years agoHelpfull: Yes(0) No(0)
• in this race, A will win by (5 min - 4 min 54 sec) = (300 sec - 294 sec) = 6 sec
  
  B covers 1000 m in 5 min
  
  => B covers 1000 m in 300 sec
  
  => B covers 1000300=103m in 1 sec=> B covers 103×6=20 m in 6 sec
  
  i.e., A can give B a start of 20 metre so that the race will end in a dead heat.
• 9 years agoHelpfull: Yes(0) No(1)
• in this race, A will win by (5 min - 4 min 54 sec) = (300 sec - 294 sec) = 6 sec
  
  B covers 1000 m in 5 min
  
  => B covers 1000 m in 300 sec
  
  => B covers 1000300=103m in 1 sec=> B covers 103×6=20 m in 6 sec
  
  i.e., A can give B a start of 20 metre so that the race will end in a dead heat.
• 9 years agoHelpfull: Yes(0) No(2)
• 20 m
  if b takes 5 min to complete 1km distance
  he covers 20m in 6 sec so a covers 1km before 6sec than b
• 6 years agoHelpfull: Yes(0) No(0)
• b covers 1000m in 300 sec
  a covers 980 m in 294 sec
  1000-980=20m
• 6 years agoHelpfull: Yes(0) No(0)
• 20 m
  (B runs 3 1/3 m per second, there are 6 seconds between a and b, therefore 6 x (3 1/3) = 20 m)
• 5 years agoHelpfull: Yes(0) No(0)