In an examination, 34% of the students failed in mathematics and 42% failed in English. If 20% of the students failed in both the subjects, then find the percentage of students who passed in both the subjects.
40%
42%
44%
46%

• total failed=34+42=76
  again 2o of them failed...so 76-20=56.
  so totally 56 failed..and reamaining 44 are passed .
  so 44 is d ans
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• let P(A)=34%(failed maths)
  P(B)=42%(FAILED ENG)
  P(A&B)=20%(FAILED IN BOTH)
  P(A OR B)=P(A)+P(B)-(PA&B)=56%
  students passed in both subjects are 100-56=44%
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