how many sero's r dere in 100! ?

• counting number of zeros at the end of n!
  value will be
  n/5 + n/5^2 + n/5^3 + n/5^4 + ..........
  the integral value of this sum will be the total number of zeros.
  in this question n=100
  100/5 + 100/5^2 + .......
  the integral value is 20+4=24.
• 12 years agoHelpfull: Yes(37) No(0)
• 100/5=20
  20/5=4
  20+4=24
  
• 12 years agoHelpfull: Yes(11) No(1)
• We need to look at the prime factors that make up 100!. Each time we multiply a factor of 2 and a factor of 5 together we get 10, which adds a zero. Obviously there are more factors of 2 than 5. So the answer to the question is to find the number of factors of 5.
  
  Every fifth number starting with 5 has a factor of 5, for a total of 100/5 = 20.
  
  Every twenty-fifth number starting with 25 has a second factor of 5, for a total of
  100/25 = 24.
  
  So the total number of factors of 5, and hence the number of zeros at the end is:
  
  20 + 4 = 24
• 12 years agoHelpfull: Yes(10) No(0)
• counting number of zeros at the end of n!
  value will be
  n/5 + n/5^2 + n/5^3 + n/5^4 + ..........
  the integral value of this sum will be the total number of zeros.
  in this question n=100
  100/5 + 100/5^2 + 100/5^3 + .......
  the integral value is 20+4=24.
• 12 years agoHelpfull: Yes(4) No(0)
• 24?
  divide 100 by 5, and then add last two quotients
• 12 years agoHelpfull: Yes(3) No(0)
• no sero will be there :)
  but 24 zeros will be there
• 12 years agoHelpfull: Yes(3) No(0)
• 100/5=20 AND 100/25=4
  THAN 20+4=24.
• 12 years agoHelpfull: Yes(3) No(0)
• it is lyk
  100/5=20
  100/25=4
  now value of 5^3 exceeds 100 so no further calculation
  ans is =20+4=24
• 12 years agoHelpfull: Yes(2) No(0)
• Let’s count the 5′s first. 5, 10, 15, 20, 25 and so on making a total of 20. However there is more to this. Since 25, 50, 75 and 100 have two 5′s in each of them (25 = 5 * 5, 50 = 2 * 5 * 5, …), you have to count them twice. This makes the grand total 24. For people who like to look at it from a formula point of view
  
  Number of 5′s = 100/5 + 100/25 + 100/125 + … = 24
  so the toatal num of 2's is 97 in 100!
  now multipling wit 5*2 we'll get 0
  total 24 pairs are der so the answer is 24
• 12 years agoHelpfull: Yes(1) No(0)
• (100/5)+(100/5^2)=24
• 12 years agoHelpfull: Yes(1) No(0)