A number ab3133ab is divisible by 12.
find minimum value of (a+b) ?

• answer is 4..
  for divisible by 12;
  the no. is devided by 3,4
  now, for 3
  a+b+3+1+3+3+a+b= 2(a+b)+10............(1)
  for 4;
  last two digit devided by 4
  it means; ab/4.........................(2)
  from equestion 1 and 2
  suitable value is of (a+b)=4;
  a=0, b=4;
• 12 years agoHelpfull: Yes(19) No(5)
• i think answer vil b 4. bcz a=4 b=0. so min value of a+b=4.
  
  but in some site its given 7.
  
  plz tell wich vil b correct.
• 12 years agoHelpfull: Yes(18) No(9)
• the answers are depends on given condition.if a and b are non zero values,then u will get 7 otherwise answr is 4
• 12 years agoHelpfull: Yes(13) No(1)
• a+b=4(minimum)
  as for 12 divisibility.. multiple of 3 and 4..
  multiple of 3:-
  10+2(a+b) its sum should be divisible of 3..
  i.e. 4+0;3+6... like this so leat value which is also divisible by 4 will be
  4+0
  so ans 4
• 12 years agoHelpfull: Yes(4) No(0)
• in dis question ask's the minimum value so it should be 4.
• 12 years agoHelpfull: Yes(4) No(0)
• Ans is 7.
  a number to b divisible by 12 must be divisible by 3 &4
  For 3 sum of digits must b divisible by 3.
  For 4 last two digits must b divisible by 4.
  a & b can be 1 & 6
• 12 years agoHelpfull: Yes(3) No(4)
• In this question the answer is always 4. if a and b are non-zero values then a+b will be 4 i.e. 0 and 4.
• 12 years agoHelpfull: Yes(2) No(1)
• the condtn fr divisibily by 12 z it shold be divide by 3,4...
  so the sum of a+b=4 ans
• 12 years agoHelpfull: Yes(2) No(0)
• answer is 4 bcz it has to be divisble by both 2 and 3 as per by divisbility rule of 12
  
• 12 years agoHelpfull: Yes(2) No(0)
• for question ab313ab ans is 7
• 12 years agoHelpfull: Yes(1) No(2)
• In this question the answer is always 4. if a and b are non-zero values then a+b will be 4 i.e. 0 and 4.
  otherwise a = 1 and b =3
• 12 years agoHelpfull: Yes(1) No(6)
• a=4 and b=0
• 12 years agoHelpfull: Yes(1) No(1)
• ans is 4 we know that a no. is divisible by 12 only when it is divisible by 3 and 4 so for satisfying these conditions we have sum of digits as a+b+3+1+3+3+a+b/3 which gives 2(a+b)+10/3 and also for no. divisible by 4 last 2 digit must be divisible by 4 so let a=4 and b=0 so for div by 3 we have 2*4+10/3=6 so this criteria is satisfied and for div by 4 last digit is 40 which is divisible by 4 and one case is also when we have a=5 and b=2 so 2*7+10/3=8 and 52/4=13 but minimum value is 4+0 ie ans would be 4
• 10 years agoHelpfull: Yes(1) No(0)
• this number can be divisible by 12 if last digits would be
  12,24,36,48,60,72,84,96........
  here only two palces given ie ab so max valu of ab will be 96
  so add 9+6=15
  ans
• 12 years agoHelpfull: Yes(0) No(4)