A cyclist started at 7 am to a place with speed 10km/hr. after reaching the place, due to cycle repair he waited for 35 min and started return journey by walk with speed 1km/hr and reached the starting place at 1pm then what is the distance between two places?

• let d=x
  10=x/t1 1=x/t2
  time duration from 7am to 1pm =6hours but waited there for 35 minute
  total time for whole journey 5h25min
  t1+t2=5h25min=65/12
  x/10+x=65/12
  x=325/66=4 61/66
• 9 years agoHelpfull: Yes(1) No(0)
• let distance between the two place be x km
  the time taken by cyclist to reach from place1 to place2 with speed of 10 km/hr=x/10 hr
  wait time=35/60hr
  the time taken by the cyclist from place2 to place1 with speed of 1 km/hr=x/1 hr
  total time taken=6 hr
  so x/10 +35/60 +x/1 =6
  by calculation x=325/66
• 9 years agoHelpfull: Yes(0) No(0)