If 5x + 2y + z = 81, where x, y and z are distinct positive integers, then find the difference between the
maximum and the minimum possible value of x + y + z.

• AS x+y+z is maximum when x=1,y=2 and z=72,
  then x+y+z=75
  x+y+z is minimum when x=15 y=2 z=2
  x+y+z=19
  difference between the two terms is 75-19=56
• 9 years agoHelpfull: Yes(0) No(1)