A father purchases dress for his daughter. The dresses are of same color but of different size. The dress is kept in dark room. What is the probability that all the three will not choose their own dress....

• Proper Selections: A B C
  A C B
  C B A
  B A C (ie. total 4)
  
  Improper selection: B C A , C A B because all should be wrong (ie. total 2)
  Probability for improper selection= 2/6 = 1/3
• 12 years agoHelpfull: Yes(29) No(2)
• ABC
  ACB
  BAC
  BCA
  CAB
  CBA
  OUT ABOVE 6 SAMPLE SPACE
  BCA & CAB OUR FAVOURABLE
  HENCE THE REQUIRED PROBABILITY IS= 2/6=1/3 ANS
• 12 years agoHelpfull: Yes(12) No(0)
• 1st 1 chosing the wrong dress has a probability of 2/3!next 1 has the probability of 1/2 and so the 3rd daughter must choose the wrong one i.e. probability 1.so ans=2/3.1/2.1=1/3
• 12 years agoHelpfull: Yes(7) No(0)
• 1/3 is the correct answer.........
• 12 years agoHelpfull: Yes(3) No(0)
• Proper Selections: A B C
  A C B
  C B A
  B A C (ie. total 4)
  
  Improper selection: B C A , C A B because all should be wrong (ie. total 2)
  Probability for improper selection= 2/6 = 1/3
• 12 years agoHelpfull: Yes(3) No(1)
• total sample=3!=6
  can be wrong=3!(1-1/1!+1/2!-1/3!)=2
  probabiblity is:2/6=1/3
• 12 years agoHelpfull: Yes(2) No(0)