LCM of two prime numbers x and y(x>y)is 161.The value 3y-x is :
(a)-2
(b)-1
(c)1
(d)2

• answer is -2. by hit and trial.. x=23 and y=7
• 11 years agoHelpfull: Yes(6) No(4)
• As both are prime numbers it's obvious xy=161
  so, x=23 and y=7 as x>y
  so, 3y-x=3x7-23=-2(Ans).
  
• 11 years agoHelpfull: Yes(4) No(1)
• Answer: A) -2
  
  Explanation:
  
  H. C. F of two prime numbers is 1. Product of numbers = 1 x 161 = 161.
  
  Let the numbers be a and b . Then , ab= 161.
  
  Now, co-primes with product 161 are (1, 161) and (7, 23).
  
  Since x and y are prime numbers and x >y , we have x=23 and y=7.
  
  therefore 3y-x = (3 x 7)-23 = -2
• 9 years agoHelpfull: Yes(2) No(0)
• Ans is -2) Because 23x7=161
  so x=23 and y=7, 3x7-23=-2.
• 11 years agoHelpfull: Yes(1) No(3)
• 23 and 7 ans is -2
• 11 years agoHelpfull: Yes(0) No(3)
• -2
  the lcm of 7 & 23 is 161
  3(7) - 23= -2
• 9 years agoHelpfull: Yes(0) No(0)