A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?
A. Rs. 4991 B. Rs. 5991
C. Rs. 6001 D. Rs. 6991

• a^2+b^2+c^2 = ab+bc+ca is possible only if a = b = c
  which means (a+b)/c = 2
  So the value of (a+b)/c is always equal to 2
• 12 years agoHelpfull: Yes(6) No(0)
• a^2+b^2+c^2 = ab+bc+ca
  => 2a^2+2b^2+2c^2 = 2ab+2bc+2ca
  => (a-b)^2+(b-c)^2+(c-a)^2 = 0
  => a=b=c
  (a+b)/c is equal to 2.
• 12 years agoHelpfull: Yes(1) No(0)
• i think it is 2...just consider values of a,b,c as 1,1,1...which satisfies the given condition...hence (a+b)/c=2...
• 12 years agoHelpfull: Yes(0) No(1)
• a=1, b=1, c=1
  1^2+1^2+1^2 = 1*1 + 1*1 + 1*1
  3=3;
  (a+b)/c=2...Ans
  
• 12 years agoHelpfull: Yes(0) No(0)
• average = sum of all the sale/number of months
  =6435+6927+6855+7230+6562/5
  = 34009
  for average of 6500 for 6 months=6500*6=39000
  39000-34009=4991
  for his 6 month sale should be Rs4991
• 8 years agoHelpfull: Yes(0) No(0)