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Three unbiased dice are thrown. Find the probability of getting sum 10.
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- 27/216 ... see the solution in the later question.. this question is repeated
- 12 years agoHelpfull: Yes(27) No(2)
- ans is 27/216
- 12 years agoHelpfull: Yes(7) No(0)
- 24/6*6*6=1/9
- 12 years agoHelpfull: Yes(3) No(11)
- ans is 1/8
- 12 years agoHelpfull: Yes(3) No(0)
- ans is 27/216
- 12 years agoHelpfull: Yes(1) No(0)
- 27/216 dis is the right answer
- 12 years agoHelpfull: Yes(1) No(0)
- Total combinations=6*6*6=(bcz der r 3 dices)
Total no. of combinations having sum 10=26 [like (1,4,6),(1,5,5),(1,6,4)..& so on]
so probability of getting sum 10=26/216=13/108=0.12037 - 12 years agoHelpfull: Yes(0) No(20)
- ANS 27/216
- 8 years agoHelpfull: Yes(0) No(0)
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