a,b and c are non -ve integers. If 28a+30b+31c=365 what is the value of a+b+c?
A. Greater than 12 B. Less than 11 C.11 D.12

• 12
  number of month with in a year
• 12 years agoHelpfull: Yes(75) No(2)
• a=1
  b=4
  c=7
  
  a+b+c=12
• 12 years agoHelpfull: Yes(9) No(1)
• snehil you are correct...wonderful answer
• 12 years agoHelpfull: Yes(5) No(1)
• As 6 couples are there so we can select 1 couple(means 2 persons) by 6C1
  Now to select remaining 2 persons we will have 3 cases:-
  1. Select 2 males
  2. Select 2 females
  3. Select 1 male and 1 female(Leaving already selected pertner)
  So,
  Slection of 4 persons will be:-
  for Case 1: 6C1*5C2
  for Case 2: 6C1*5C2
  for Case 3: 6C1*5C1*4C1 (4C1 is taken bcz we have removed the pweson of same couple)
  Now, Selecting 4 persons without any constraint will be 12C4
  So, total probability will be:-
  
  [6C1*5C2 + 6C1*5C2 + 6C1*5C1*4C1]/12C4
  i.e P = 16/33
• 12 years agoHelpfull: Yes(4) No(4)
• 28(a+b+c)+2b+3c=365
  put a+b+c=12 then 2b+3c=29,so we have c=7,b=4 and a=1
  a+b+c=12
• 12 years agoHelpfull: Yes(4) No(0)
• nice logic snehil,, thanks..
• 12 years agoHelpfull: Yes(3) No(1)
• 28(a+b+c)+2b+3c=365
  a+b+c=12
  28*12+2b+3c=365
  2b+3c=365-336
  2b+3c=29
  a=2,b=1,c=9
• 12 years agoHelpfull: Yes(2) No(1)
• a=1
  b=5
  c=6
  a+b+c=12 ans
• 12 years agoHelpfull: Yes(1) No(14)
• yes the ans is 12.
• 12 years agoHelpfull: Yes(0) No(2)
• 12
  it the mutile so the the number of year comes..
  
• 12 years agoHelpfull: Yes(0) No(1)
• n1 snehil...
  awessome logic..
  
• 12 years agoHelpfull: Yes(0) No(0)
• sorry friend my last ans i wrong.
  1+4+7=12 is right
• 12 years agoHelpfull: Yes(0) No(0)
• SRIKHAKOLLU :thnx
• 12 years agoHelpfull: Yes(0) No(0)