in a class consisting of boys and girls the boys constituted 55% of the total strength of the class if on a particular day 40% of the boys and 60% of the girls were present.what is the % of the total strength absent from the class and % of the total strength present in the class?

• boys constituted=55%
  so girls=100-55=45%
  boys present=55*40/100=22.0%
  girls present=45*60/100=27.0%
  totalpresent in class=22+27=49%
  total apsent in clss=100-49=51%
• 12 years agoHelpfull: Yes(58) No(0)
• assume total strength is 100....
  boys=55
  grls=45
  present boys=40% of 55=22
  present grls=60% of 45=27
  total present student=49=49%
  total absent student=51=51%
• 12 years agoHelpfull: Yes(13) No(0)
• 49%...
  ((40*55)+(45*60))/100
  49per
• 12 years agoHelpfull: Yes(3) No(0)
• let the total student be 100
  then out of 55% r boys
  so boys r 55
  and girls r 45
  now present student is
  40% of boys = (40/100)*55=22
  and 60% of girl=(60/100)*45=27
  so total present is 49
  and absent student is 100-49=51
  m right....
• 12 years agoHelpfull: Yes(3) No(0)
• 49% PRESENT AND 51% ABSENT
  
• 12 years agoHelpfull: Yes(2) No(0)
• TOTAL STRENGTH =X
  BOYS=55%,SO GIRLS=45%
  BOYS PRESENT=(40/100)*(55/100)X=0.22X
  GIRLS PRESENT=(60/100)*(45/100)X=0.27X
  TOTAL PRESENT=0.49X=49%
  TOTAL ABSENT=X-0.49X=0.51%=51%
• 12 years agoHelpfull: Yes(2) No(1)
• present=49%
  absent=51%
• 12 years agoHelpfull: Yes(1) No(0)
• let total strength =x
  so x*(55/100)*(40/100)+x(45/100)*(60/100)
  x*(0.49)
  x*49/100
  ie 49% are present
• 12 years agoHelpfull: Yes(1) No(1)