1 2 2 3 3 3 4 4 4 4 1 1 2 2 2 2 3 3 3 3 3 3 4 4 4 4 4 4 4 4 ..................what is the 2852 term? wit xplanation

• each time the number become double their strength jst as 10 20 40....and soon so wehve to find the last limit as 10 20 40 80 160 320 640 1280 total 2550
  here ratio they are incrementing is 1:2:3:4 always in 1280 the no of 1s 2s 3s nd 4s is as 128:256:384:512
  so what left is 2852-2550=302
  no of 1s in next iteration ll b jst double of previous eg 128*2=256
  and no of 2s ll be 512
  so substractin 302 -256= will give range for 2
  ans is 2
• 12 years agoHelpfull: Yes(15) No(2)
• D series is from first 1 to last 4 is 10 no's, d series is 10,20,30.... 2852/10= 28 th series, 2801 th wld b 1, 28 times, so, 2829th to 2857 wuld be 2..
  So, d ans is 2..
• 12 years agoHelpfull: Yes(3) No(2)
• ans: 4
  10+20+30+...+2852
  10n(n+1)/2=2852
  then n=24
  apply n value to n(n+1)/2 then get 3000
  24*4=96.then in last part has 96 4's. 3000-2852=72 then 2852 is a 72 4.
• 12 years agoHelpfull: Yes(1) No(7)
• i think ans is 3......
  sorry due to net problem i can't explain
• 12 years agoHelpfull: Yes(1) No(2)
• i think ans will be 3
  As 10+20+30.....=2852
  10*n(n+1)/2=2852
  solving n=24
  as 111....24times2222....48times3333....72times so
  24+48+20=92 so 3 will be ans.
• 12 years agoHelpfull: Yes(1) No(0)
• ans should be 1
  for n=1 no of terms= 10
  n=2 terms= 20
  2800 terms for n= 280
  then 2852 we get by n=281 so there will be 281 1s
  from 2801 to 3081 there will be 1 so 2852 term is 1.
• 12 years agoHelpfull: Yes(0) No(4)
• 10+20+30+...+2852
  10n(n+1)/2
• 12 years agoHelpfull: Yes(0) No(2)