Find the number of sides of a regular convex polygon whose angle
is 40degrees.

• if the polygon s of n sides then the interian angle is given by (n-2)*180/n.
  so (n-2)180/n =40.
  we get n=18/7..since n is a integer so we conclude that no such polygon is posible..
• 14 years agoHelpfull: Yes(10) No(0)
• (n-2)*180/n.............zero
• 14 years agoHelpfull: Yes(3) No(1)
• answer is 9
• 14 years agoHelpfull: Yes(3) No(5)
• The measure of one vertex angle of a regular polygon is given by:
  %28n-2%29180%2Fn where n is the number of sides of the regular polygon...and, of course, it goes without saying, that n must be an integer >2(i.e, 3, 4, 5, 6, ...).
  If the measure of one vertex angle of a regular polygon is 40 degrees, then we can write:
  %28n-2%29180%2Fn+=+40 Simplify and solve for n.
  %28180n-360%29%2Fn+=+40 Multiply both sides by n.
  
  180n+-+360+=+40n Add 360 to both sides.
  180n+=+360%2B40n Subtract 40n from both sides.
  140n+=+360 Divide both sides by 140.
  n+=+2.57 This is not possible since a regular polygon mu
• 13 years agoHelpfull: Yes(2) No(2)