Syntel
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Numerical Ability
Geometry
Find the number of sides of a regular convex polygon whose angle
is 40degrees.
Read Solution (Total 4)
-
- if the polygon s of n sides then the interian angle is given by (n-2)*180/n.
so (n-2)180/n =40.
we get n=18/7..since n is a integer so we conclude that no such polygon is posible.. - 13 years agoHelpfull: Yes(10) No(0)
- (n-2)*180/n.............zero
- 13 years agoHelpfull: Yes(3) No(1)
- answer is 9
- 13 years agoHelpfull: Yes(3) No(5)
- The measure of one vertex angle of a regular polygon is given by:
%28n-2%29180%2Fn where n is the number of sides of the regular polygon...and, of course, it goes without saying, that n must be an integer >2(i.e, 3, 4, 5, 6, ...).
If the measure of one vertex angle of a regular polygon is 40 degrees, then we can write:
%28n-2%29180%2Fn+=+40 Simplify and solve for n.
%28180n-360%29%2Fn+=+40 Multiply both sides by n.
180n+-+360+=+40n Add 360 to both sides.
180n+=+360%2B40n Subtract 40n from both sides.
140n+=+360 Divide both sides by 140.
n+=+2.57 This is not possible since a regular polygon mu - 13 years agoHelpfull: Yes(2) No(2)
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