a+b+c=0, then roots of ax^2+bx+c=0 is

• Best Answer - Chosen by Asker
  a+b+c=0, then roots of ax^2+bx+c=0 is 1.imag,
  2.real 3.coincidental 4.zero?
  
  Here, we have,
  x = [-b +/- sqrt(b^2 - 4ac)] / 2a ................... [1]
  Since,
  a+b+c = 0 ==> b = -(a+c)
  b^2 = (a+c)^2 = a^2+c^2 +2ac
  
  b^2 -4ac = a^2+c^2-2ac = (a-c)^2 ........... [2]
  
  From [1] and [2], we get,
  x = [a+c +/- (a-c)] / 2a
  
  x = 1, and x = c/a
• 14 years agoHelpfull: Yes(43) No(6)
• quadratic Roots of algebraic expression Ax^2+Bx+c=0 is -B/A, C/A
• 10 years agoHelpfull: Yes(2) No(4)