hOW many values of C in equation X^2-5X+C results in Rational roots which are integers??

options:
a.) 1
b.) 3
c.) 6
d.) Infinite

• I think option d is Correct.
  (-b(+ or -)sqrt(b^24ac))/2a=0;
• 9 years agoHelpfull: Yes(7) No(3)
• d) Infinite
• 9 years agoHelpfull: Yes(7) No(2)
• i think it is 3..
  c will be 0,4,6
• 9 years agoHelpfull: Yes(7) No(3)
• for positive C, i think number of value are 3
• 9 years agoHelpfull: Yes(2) No(5)
• sqrt(b^2-4ac)>=0 so sqrt(25-4c)>=0 => 25>=4c => 6.25>=c
  so the possible value to c can be 1,2,3,4,5,6.
• 9 years agoHelpfull: Yes(2) No(1)
• solution:::(d) Infinite
  sqrt(b^2-4ac)>=0 so sqrt(25-4c)>=0 => 25>=4c => 6.25>=c
  So the possible values of c can be infinite(c
• 9 years agoHelpfull: Yes(2) No(3)
• ans:b bcz by substitute the values 0,4,6 in c we get a perfect value of x
• 9 years agoHelpfull: Yes(1) No(0)
• Ans id 6.. bcoz iff we put c=6,x^2-3x-2x+6,,,, so x=2,3
• 9 years agoHelpfull: Yes(0) No(2)
• ans is (D)
  
• 9 years agoHelpfull: Yes(0) No(0)
• C has 0,4,6 values in positive integer
  C= -6,-24,-36,-50 and so on in negative integer therefore infinite solution will exit
• 9 years agoHelpfull: Yes(0) No(0)
• discriminant (D)= (25-4c)/2
  for real roots D>=0
  so (25-4c)/2>=0
  25-4c>=0
  25>=4c
  c
• 7 years agoHelpfull: Yes(0) No(0)
• discriminant(D) = (b^2-4(a)(c)) = (25-4c)
  
  for c = -15, -25, -45, -35, -55, -65, -75, -85, -95, -105..... discriminant root is perfect
  
  so infinite c values
• 7 years agoHelpfull: Yes(0) No(1)
• @sywhussaini
  discrinant = 15^2, 25^2, 35^2, 45^2, 55^2, 65^2, 75^2, 85^2....
  not c
  SO c = -50, -150, -300, -500, -750, -1050, -1400, -1800.....
• 7 years agoHelpfull: Yes(0) No(0)
• 3.i.e =0,4,6
• 7 years agoHelpfull: Yes(0) No(0)
• right ans is c
  Explanation.....
  b^2-4ac>=0
  b=5, a=1
  so c will 0,1,2,3,4,5
• 7 years agoHelpfull: Yes(0) No(1)