Elitmus
Exam
Numerical Ability
Time and Work
A and B can finish a work 30 days if they work together. They worked together for 20 days and then B left. A finished the remaining work in another 20 days. In how many days A alone can finish the work?
Options
1) 60
2) 50
3) 40
4) 30
Read Solution (Total 8)
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- 20(1/30)+20/a=1
a=60 - 9 years agoHelpfull: Yes(12) No(0)
- if A+B do the work in 1 days 1/30
then in 20 days 20/30
remaining work is 1/3
now let A completes the work in x days
so work done by A in one day is 1/x
so in 20 days 20/x=1/3
so the x=60
ans is 60
- 9 years agoHelpfull: Yes(5) No(0)
- 60 is the right anwser
please use basic approach to slove this question - 9 years agoHelpfull: Yes(1) No(0)
- 60
................ - 9 years agoHelpfull: Yes(1) No(0)
- A+B=1/30
A+B=20/30 FOR 20 DAYS
Remaining work =1/3
1/3 work is cmplted by A is 20 days
cmplt wrk is in 60 days by A - 9 years agoHelpfull: Yes(0) No(0)
- A and B can do work in 30 days
so 1 days both will be work 1/30
so 20 days both will be work 20/30
so work left is 1-(20/30)=10/30 work done by A IN 20 DAYS so A can finish the work (30*20)/10
= 60 days
- 9 years agoHelpfull: Yes(0) No(0)
- 60
better to solve through option - 8 years agoHelpfull: Yes(0) No(0)
- A+B in 60 days
A+B worked for 20 days hence 66.6% work complete.
B left
A did remaining 33.3% work in 20 days. Hence capacities are same hence individually both can take 60 days to complete - 8 years agoHelpfull: Yes(0) No(0)
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