what is the unit digit of 21^3*21^2*34^7*46^8*77^8 ?

• 4
  21^3*21^2*34^7*46^8*77^8
  => 1^3*1^2*4^7*6^8*7^8
  => 1*1*4*6*1
  =>24
  So 4
• 12 years agoHelpfull: Yes(14) No(0)
• ans=4
  multiply the unit digits
• 12 years agoHelpfull: Yes(8) No(0)
• for these type of questions take unit digit with its power..
  here
  1^3 * 1^2 * 4^7 * 6^8 * 7^8 again unit digit
  1*1*4*6*1 =24 hence 4
• 12 years agoHelpfull: Yes(3) No(1)
• Guys i did't get questions from here but posted questions gives ability to crack aptitude.
  
  all the best.
• 12 years agoHelpfull: Yes(1) No(1)
• by breaking the terms ,,it will come 4
• 12 years agoHelpfull: Yes(1) No(0)
• what is the solution if the prob is like
  22^22*0.44^33*0.21^7
• 6 years agoHelpfull: Yes(0) No(0)