if p x ax 4 bx 3 cx 2 dx e has roots at x 1 2 3 4 and

@DHIRAJ SINGH:
actually roots are given so we can easily get the equation
p(x)=(x-1)(x-2)(x-3)(x-4)
if we put x=0,we get p(0)=24 but in the question it is mention p(0)=48
so equation p(x) should multiply by 2
p(x)=2(x-1)(x-2)(x-3)(x-4)
i think nw u get it
12 years agoHelpfull: Yes(4) No(0)
48 is the answer
12 years agoHelpfull: Yes(1) No(1)
Chintan the reason fo it is the given equation has roots as 1,2,3,4 which makes the equation: p(x)=(x-1)(x-2)(x-3)(x-4).
12 years agoHelpfull: Yes(1) No(0)
can anyone explain how
p(x)=(x-1)(x-2)(x-3)(x-4)
the actual value of p(x)is
p(x)=ax^4 + bx^3 + cx^2 + dx + e
12 years agoHelpfull: Yes(0) No(1)
ya okk....
i got tad
thankss
12 years agoHelpfull: Yes(0) No(0)
@Piyush :
i got the point e=48 but,
i didn't understand the point 24..
as well i didn't get the p(x)=2(x-1)(x-2)(x-3)(x-4)..
where does 2 come from?
12 years agoHelpfull: Yes(0) No(0)

if p(x)=ax^4 + bx^3 + cx^2 + dx + e has roots at x=1,2,3,4 and p(0)=48, what is p(5)?
(1)48
(2)24
(3)0
(4)50