When numbers are written in base e,we have 12*25=333 The value of e is? plz explian this ??

• 12 in base 10=(10*1+2)
  25 in base 10=(10*2+5)
  
  similarly,
  
  12 in base 7=(b*1+2)&
  25 in base 7=(b*2+5)
  
  now 333 in base 10=(10*10*3+10*3+3)
  333 in base 7=(b*b*3+b*3+3)
  
  so,(b*b*3+b*3+3)=(b*2+5)+(b*1+2)
  solve
  answer will be 7.
• 11 years agoHelpfull: Yes(11) No(1)
• Normally (in base 10) : 12*25=300
  But it is given that 12*25=333
  It means base will be definitely less than 10
  So Check for options near 7 and
  you will find it that 7 is the correct answer.
• 11 years agoHelpfull: Yes(5) No(8)
• 12 in base 10=(10*1+2)
  25 in base 10=(10*2+5)
  
  similarly,
  12 in base e=(e*1+2)&
  25 in base e=(e*2+5)
  
  now 333 base 10=(10*10*3+10*3+3)
  then 333 base e =(e*e*3+e*3+3)
  
  so,(e*e*3+e*3+3)=(e*2+5)*(e*1+2)
  by soving this we get e=7.
  
• 11 years agoHelpfull: Yes(3) No(1)
• awesome question
• 11 years agoHelpfull: Yes(2) No(2)
• Ans will be 7
  in case of base 7
  7 is represent as (7*1+0)=0
  8 ,, ,, ,, (7*1+1)=1
  10 ,, ,, ,, (7*1+3)=3
  ..........................
  13 ,, ,, ,, 6
  14 ,, ,, ,, 0
  
  so, 12
  25 => 60
  24
  .......
  333
  333 as 2*5=10 for 0 its 3 again 6+4=10 for 0 its 3 and 1+2 = 3 for rest
• 11 years agoHelpfull: Yes(2) No(0)
• 12 in base 7= 9 in base 10.
  25 in base 7 = 19 in base 10.
  333 in base 7 = 171 in base 10.
  
  9*19=171
• 11 years agoHelpfull: Yes(1) No(6)
• all these answers r wrong,,,just substitute value 7 in that,,,it did not get
  
• 11 years agoHelpfull: Yes(1) No(2)
• didnt get it..explain!
• 11 years agoHelpfull: Yes(0) No(5)