what is the largest positive integer n for which n3+47 is divisible by n+5

• n3+47=10n+3+47=10n+50=10(n+5)
  which is always divisble by n+5
• 11 years agoHelpfull: Yes(6) No(6)
• (n^3+47)/(n+5) = (n^2-5n+24)+ (n-73)/(n+5)
  
  If n^3+47 is divisible by n+5, then n-73 =0
  n=73
• 11 years agoHelpfull: Yes(5) No(4)
• n^3+47=(n^3+125)-78
  [((n^3)+(5^3))-78]/(n+5)=[(n+5)(n^2-5n+25)-78]/(n+5)=(n^2-5n+25)-(78/n+5)
  so,n^3+47 is divisible by n+5 when n+5 must be equal to 78
  so,n+5=78=>n=73
• 10 years agoHelpfull: Yes(1) No(0)
• I got the solution as 460 is this correct??
• 11 years agoHelpfull: Yes(0) No(6)
• plz explain in detail...
• 10 years agoHelpfull: Yes(0) No(0)
• can anyone explain me
• 10 years agoHelpfull: Yes(0) No(0)